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4 years ago

Can I get help on this please? You will be marked Brainliest and 5 ⭐️ Thank you!!!

Mathematics

2 answers:

miskamm [114]4 years ago

7 0

Answer:

y = 50x

Step-by-step explanation:

the equation for this is y = 50x because for every 50 units we go up by on the graph we go 1 unit to the right so:

slope-intercept form: y = mx + b where m is the slope and b is the y-intercept. Our y-intercept is 0 because that is where our line intersects the y-axis and because it is 0 we do not need to put it in the equation.

y = 50x

____ [38]4 years ago

4 0

Answer:

y=50x every week it goes up 50

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(x+16)°<br> (4x-5)°<br> Find the measure of the angle.<br> I

o-na [289]

$4x - 5 = x + 16$

Subtract the sides of the equation plus 5

$4x = x + 16 + 5$

$4x = x + 21$

Subtract the sides of the equation minus x

$3x = 21$

Divided the sides of the equation by 3

$\frac{3}{3} x = \frac{21}{3} \\$

$x = 7$

So the measure of the angle equals :

$4(7) - 5 = 28 - 5 = 23$

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

6 0

3 years ago

-__y^2-[-5y-y(-7y-9)]-[-y(15y+4)]=0 please help I don’t know how to find the missing coefficient in the blank

Rama09 [41]

Hello,

if y≠0 then

$ay^2-[-5y-y(-7y-9)]-[-y(15y+4)]=0\\\\ay^2-[-5y+7y^2+9y]-[-15y^2-4y]=0\\\\ay^2+5y-7y^2-9y+15y^2+4y=0\\\\ay^2+8y^2=0\\\\(a+8)y^2=0\\\\a=-8\\\\\\$

4 0

3 years ago

Read 2 more answers

Will give brainiest if correct

bezimeni [28]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The answer please!<br> Thank you have have a great night.

larisa [96]

C would be the correct answer.

All of the numbers are integers, which is a subset in rational numbers. The numbers (0-3) are all whole numbers. The whole numbers are a part of integers, completing the chart.

3 0

4 years ago

PLEASE can someone explain why The exact value of sec ( π/6) is 2 /√ 3 ??

Umnica [9.8K]

$\bf sec\left( \frac{\pi }{6} \right)\qquad recall\to sec(\theta)=\cfrac{1}{cos(\theta)}\qquad thus
\\\\
sec\left( \frac{\pi }{6}\right)\iff \cfrac{1}{cos\left( \frac{\pi }{6}\right)}
\\\\\\
\textit{check your Unit Circle for what the }cos\left( \frac{\pi }{6}\right)\ is
\\\\\\
\cfrac{1}{\frac{\sqrt{3}}{2}}\implies \cfrac{\frac{1}{1}}{\frac{\sqrt{3}}{2}}\implies 
\cfrac{1}{1}\cdot \cfrac{2}{\sqrt{3}}\implies \cfrac{2}{\sqrt{3}}$

3 0

3 years ago