A new youth activity center is being built in Erie. The perimeter of the rectangular playing field is 490 yards. The length of t
he field is 5 yards less than quadruple the width. What are the dimensions of the playing field?
1 answer:
P = 2(L + W)
P = 490
L = 4W - 5
now we sub and solve
490 = 2(4W - 5 + W)
490 = 2(5W - 5)
490 = 10W - 10
490 + 10 = 10W
500 = 10W
500/10 = W
50 = W <===
L = 4W - 5
L = 4(50) - 5
L = 200 - 5
L = 195 <===
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