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Julli [10]
4 years ago
8

Use Bayes' rule to find the indicated probability. The incidence of a certain disease on the island of Tukow is 4%. A new test h

as been developed to diagnose the disease. Using this test, 91% of those who have the disease test positive while 4% of those who do not have the disease test positive (false positive). If a person tests positive, what is the probability that he or she actually has the disease?
Mathematics
1 answer:
lina2011 [118]4 years ago
7 0
These are the events in the question above:

<span>D - has disease 
</span>
<span>H - healthy (does not have disease) 
</span>
<span>P - tests positive </span>

<span>It is the probability that a person has the disease AND tests positive divided by the probability that the person tests positive.
</span>
Sick, + [.04*.91] = .0364 

<span>Sick, - [.04*.09] = .0036 </span>

Healthy, + [.96*.04] = 0.0384

<span>Healthy, - [.96*.96] = .9216 

</span>
.0364 / (.0364 + .0.0384) = 0.487
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Perimeter = 2* width + 2*length

Ratio becomes:

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Answer:

The lengths are

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Step-by-step explanation:

Let the side against the barn be xft

We were told that the adjacent side is 4ft more than the side against the barn. This means it has a length of (x + 4)ft.

Lastly, we are told that the hypotenuse is 8ft longer than the side along the barn I.e (x + 4 + 8)ft = ( x + 12)ft.

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