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andreyandreev [35.5K]
3 years ago
12

Given that ∠CEA is a right angle and bisects ∠CEA, which statement must be true?

Mathematics
2 answers:
loris [4]3 years ago
8 0
Given that ∠CEA is a right angle which has been bisected by BE, then:
∠CEB=∠BEA
thus each angle will be complementary to each other, hence the size will be:
90/2=45°
hence the correct statement.
<span>m∠CEB = 45°</span>
Elden [556K]3 years ago
4 0

Answer:

m∠CEB = 45°  is true.

Step-by-step explanation:

We are given that,

∠CEA = 90° and BE bisects the ∠CEA.

Since, we know,

'When a line bisects an angle, it divides the angle into two equal parts'

So, we get,

∠CEB = ∠BEA = \frac{90}{2} = 45°

So, from the options we see that,

Options A, B and D cannot be true. So, only option C is correct.

That is, m∠CEB = 45°

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Read 2 more answers
30 points! Find the four arithmetic means between -17 and 32.
bearhunter [10]

Answer: - 7.2 , 2.6 , 12.4 and 22.2

Step-by-step explanation:

Let the arithmetic means be p , q , r ,s , therefore , the sequence becomes:

-17 , p , q , r , s , 32

The first term (a ) = -17

Last term (L) = 32

common difference (d) = ?

number of terms (n ) = 6

We will use the formula for calculating the last term to find the common difference. That  is

L = a + (n - 1 ) d

Substituting the values , we have

32 = -17 + (6-1) d

32 = -17 + 5d

32 + 17 = 5d

49 = 5d

Therefore: d = 9.8

We can therefore find the values of p , q , r , and s

p is the second term , that is

p = a + d

p = -17 + 9.8

p = -7.2

q = a + 2d

q = - 17 + 19.6

q = 2.6

r = a + 3d

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