<u>The mass of hydrogen atoms in the sample of water is 3.98g</u>
This can be solved by understanding of Avogadro's number and mole relationship concept.
<h3 /><h3>Avogadro's number</h3>
<u>This is a proportionality that relates the number of particles to the amount of substance in that sample and it is given as </u>
A molecule of water have the chemical formula as HO. This implies that for every 1 atom or molecule of oxygen, 2 hydrogen must be present.
In the question given, we have atoms of oxygen. This implies we must have
Now, let's compare this molar mass - Avogadro's number
molar mass of hydrogen = 1g/mol
From the calculation above, we would have 3.98g of hydrogen present in that particles of oxygen.
learn more on Avogadro's concept
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Molar mass FeSO₄ =151.908 g/mol
Volume = 450 mL / 1000 = 0.45 L
1 mol ----------- 151.908 g
n mol ----------- 0.8 g
n = 0.8 * 1 / 151.908
n = 0.00526 moles
M = n / V
M = 0.00526 / 0.45
M = 0.01168 mol/L⁻¹
hope this helps!
B, D and E
Explanation:
conversion factors
1c = 8oz
1pt = 2c
1qt = 2pt
For A and B
ounces to cup = 160/8 = 20c
cup to pints = 20c / 2c = 10pt
pint to quarts = 10pt/2pt = 5qt
B applies as four 1-quart and two 1-pt = 5 1-quart
Considering C
4 8oz = 32oz
160-32 = 128oz /8 = 16c/2 = 8pints C does not apply
considering D
8 * 8 = 64oz
160 - 64 = 96oz/8 = 12c/2 = 6pt/2 = 3qt
So D applies
E applies
Answer:
CaKr Na2S BaCl3 MgF. CaKr-Kr is a noble gas Na2S-not balanced BaCl3-not balanced MgF-not balanced.
Explanation: