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stealth61 [152]
4 years ago
5

A solution is prepared by adding .8 g of iron sulfate to 450mL of water

Chemistry
1 answer:
Anastasy [175]4 years ago
7 0
Molar mass FeSO₄ =151.908 g/mol

Volume = 450 mL / 1000 = 0.45 L

1 mol ----------- 151.908 g
n mol ----------- 0.8 g

n = 0.8 * 1 / 151.908

n = 0.00526 moles 

M = n / V

M = 0.00526 / 0.45

M = 0.01168 mol/L⁻¹

hope this helps!
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Answer:

2.95 g of CH₄

Explanation:

To start this, we determine the equation:

4H₂  + CO₂ →  CH₄  +  2H₂O

4 moles of hydrogen react to 1 mol of carbon dioxide in order to produce 1 mol of methane and 2 moles of water.

To determine the limiting reactant, we need to know the moles of each reactant.

8.1 g . 1 mol/ 44g = 0.184 moles of carbon dioxide

2.3 g . 1mol / 2g = 1.15 moles of hydrogen

4 moles of hydrogen react to 1 mol of CO₂

Then, 1.15 moles may react to (1.15 . 1) /4 = 0.2875 moles

We only have 0.184 moles of CO₂, so this is the limiting reactant. Not enough CO₂ to complete the 0.2875 moles that are needed.

Ratio is 1:1. 1 mol of CO₂ produces 1 mol of methane

Then, 0.184 moles of CO₂ will produce 0.184 moles of CH₄

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3 years ago
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Answer:

Option "C" is the correct answer to the following question.

Explanation:

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