True...............................
The answer is (3) CH3COOH. CH3COOH is a acid. It can ionized in water. So the solution can conduct an electric current. And the other three can not be ionized in water.
Answer:
The answer is:
(a) 
(b) NaCl
(c) 0.211 g
Explanation:
Given:
The mass of NaCl,
= 0.0860 g
The molar mass of NaCl,
= 58.44 g/mol
The volume of
,
= 30.0 ml
or,
= 0.030 L
Molarity of
,
= 0.050 M
Moles of NaCl will be:
= 
= 
= 
now,
Moles of
will be:



(a)
The reaction is:
⇒ 
(b)
1 mole of NaCl react with,
= 1 mol of 
0.0015 mol
needs,
= 
Available mol of NaCl < needed amount of NaCl
So,
The limiting reagent is "NaCl".
(c)
The precipitate formed,
= 
= 
738.1146 grams, your're welcome