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lakkis [162]
3 years ago
10

Solve photo question. Mathematics

Mathematics
2 answers:
bekas [8.4K]3 years ago
4 0
We can substitute each and check if it gives us the answer 13

1st one:
4(1)+3(6) = 13
4 + 18 = 13
22 ≠ 13
It does not satisfy the equation!

therefore, The last one is the answer after checking them all.

4(4) + 3(-1) = 13
16 - 3 = 13
13 = 13

(4, -1)

irakobra [83]3 years ago
3 0
(4,-1). 4x+3y=13. You do 4(4)+3(-1)=13. hope that helps.
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Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
A ball drops from the top of a tower. At the same time a rocket is launched from a different level of the tower.
ExtremeBDS [4]

Answer:a

Step-by-step explanation:

5 0
3 years ago
Katie wants to buy some popcorn for her family at the theater. Each small tub of popcorn costs $3 and each large tub of popcorn
Molodets [167]

For this case we propose a system of equations:

x: Represents the amount of small popcorn tubs

y: Represents the amount of large popcorn tubs

According to the data we have to:

3x + 4y = 24 (Spending all the money in your wallet)

x + y = 7 (Buying 7 popcorn tubs)

From the second equation we have:

x = 7-y

Substituting in the first equation:

3 (7-y) + 4y = 24\\21-3y + 4y = 24\\21 + y = 24\\y = 24-21\\y = 3

Thus, Katie can buy 3 large tubs of popcorn.

So:

x = 7-3\\x = 4

In addition, you can buy 4 small tubs of popcorn.

Answer:

3 large popcorn tubs.

4 small popcorn tubs.

8 0
3 years ago
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