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pentagon [3]
3 years ago
7

Which system of inequalities is represented by the graph? i need help on this for a test

Mathematics
1 answer:
olga55 [171]3 years ago
4 0

Answer:

Line 1:

We know that the dotted line is the first equation since it is the only one without an 'equal to'

We can see that the y-intercept of the line is '+2'

Now to find its slope

since slope is rise/run and we see that the slope goes down 4 units while travelling only 2 units on the x plane

So, the slope  = -2

Hence, it's formula is y _ -2x  +2

i left a dash in the equation to explain why it will be a '<'

In the graph, we can see that the shaded region is the area where values of all the graphs overlap

Hence, for the area of overlap to be below our line 1, the symbol is <

Therefore, the equation for line 1:

y < -2x + 2

This eliminated option 1 and 4 since their equation is different

Line 2:

Again in this one, the symbol will be a less than since the area of overlap is below the line but since the line is not dotted,

the symbol will be ≤ (less than or equal to)

One of the 2 remaining lines is linear and since the line in question is not linear, we know which line we are talking about

Now to find its equation

y-intercept = -1

Slope = Rise / Run

Since its y increases by 1 whenever the x increases by 2

Rise = 1      Run = 2

Slope = 1/2

Equation:

y ≤ x/2 -1

Now that we have 2 of the 3 equations, we are basically done

We can see that the only system of inequalities that satisfies our equations is 2

Hence, option 'b' is correct

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I don’t know how to do this ! Help?
dybincka [34]

Answer:

The information we need is that the angle between the sides (that is, angle TVU for triangle TVU and angle WVX for triangle WVX) need to be equal.

These angles are vertically opposite angles, because they are formed by two lines crossing, so these angles are equal.

Step-by-step explanation:

The SAS Congruence Theorem says that if two triangles have 2 equal sides and the angle between these sides are also equal, the triangles are congruent.

In this question, we know that the sides UV and VW are congruent, as V is the midpoint of UW. We also know that TV = VX, so now we have two equal sides for each triangle.

The information we need is that the angle between the sides (that is, angle TVU for triangle TVU and angle WVX for triangle WVX) need to be equal.

These angles are vertically opposite angles, because they are formed by two lines crossing, so these angles are equal.

Now we can conclude that the triangles are congruent.

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Csf%20%5Chuge%7B%20question%20%5Chookleftarrow%7D" id="TexFormula1" title=" \sf \huge
BabaBlast [244]

\underline{\bf{Given \:equation:-}}

\\ \sf{:}\dashrightarrow ax^2+by+c=0

\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.

\sf We\:know,

\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}

\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}

\underline{\large{\bf Identities\:used:-}}

\boxed{\sf (a+b)^2=a^2+2ab+b^2}

\boxed{\sf (√a)^2=a}

\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}

\boxed{\sf \sqrt{\sqrt{a}}=a}

\underline{\bf Final\: Solution:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}

\bull\sf Apply\: Squares

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}

\bull\sf Put\:values

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}

\bull\sf Simplify

\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}

\underline{\bf More\: simplification:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}

\underline{\Large{\bf Simplified\: Answer:-}}

\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}

5 0
2 years ago
Read 2 more answers
The area of a triangle is 54 cm2. The base is 18 cm. What is the height of the triangle? Let h represent the height of the trian
Margaret [11]

Hi,

h = 2 a/b so our answer would be 6. The height of the triangle is 6.

Have a great day!

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Solve for g.<br> 2(g - 13) = 12<br> g
densk [106]

Answer:

-2

Step-by-step explanation:

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