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Stells [14]
3 years ago
10

Helen has 80 books to sell.

Mathematics
1 answer:
Lorico [155]3 years ago
6 0
If all my calculations are correct Helen should make £700. If she has a 3:1 ratio that means she has 3 times as many fiction books as she does nonfiction. This means out of Helens total 80 books, 60 would be fiction and 20 would be nonfiction. Now to calculate the price, all the fiction books are £10 so that would give her £600. All the non fiction books are £5 and so that would give her £100 and then combined Helen should have £700
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You have 2\3 of a pizza left from yesterday. You divide it into 4 equal pieces. What fraction of the pizza is each piece?​
Mrrafil [7]

Step-by-step explanation:

that means we divide 2/3 by 4.

2/3 / 4 = 2/3 / 4/1 = 2/3 × 1/4 = 2/12 = 1/6

so each quarter of the remaining 2/3 pizza is actually 1/6 of the complete pizza.

7 0
2 years ago
Lim x->pi/3 ((2cosx-1)/(tan^2x-3))
beks73 [17]

You can check that the limit comes in an undefined form:

\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\dfrac{0}{0}

In these cases, we can use de l'Hospital rule, and evaluate the limit of the ratio of the derivatives. We have:

\dfrac{\text{d}}{\text{d}x}2\cos(x)-1 = -2\sin(x)

and

\dfrac{\text{d}}{\text{d}x}\tan^2(x)-3 = 2\dfrac{\tan(x)}{\cos^2(x)}=\dfrac{2\sin(x)}{\cos^3(x)}

So, we have

\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\lim_{x\to\frac{\pi}{3}} \dfrac{-2\sin(x)}{\frac{2\sin(x)}{\cos^3(x)}}=\lim_{x\to\frac{\pi}{3}}-\cos^3(x)=-\cos^3\left(\dfrac{\pi}{3}\right)

6 0
3 years ago
When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected
jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

N=\frac{12.36}{0.03+0.55^t}

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

N=\frac{12.36}{0.33+0.55^0}

N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12

A. Initially, there were 12 deer.

B. N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

8 0
3 years ago
In the triangle below, which equation can be used to solve for x?
Murrr4er [49]
U forgot the attachment
4 0
3 years ago
Read 2 more answers
Solve for x: −2(x + 3) = −2x − 6<br><br> 0<br> 3<br> All real numbers<br> No solution
Alik [6]

Answer:

  x ∈ All real numbers

Step-by-step explanation:

When the distributive property is applied to the left side, the parentheses can be eliminated and the equation becomes ...

  -2x -6 = -2x -6

This is true for all possible values of x, "all real numbers".

8 0
3 years ago
Read 2 more answers
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