3 years ago

What is 16 tens + 4 ones

Mathematics

2 answers:

aalyn [17]3 years ago

5 0

(16*0) + (4*1)
16*10 = 160
4*1 = 4
160 + 4
The answer is 164! :)

lisabon 2012 [21]3 years ago

4 0

164. :) I hope that helps! 16 tens equals 160. 4 ones equals 4. 160+4=164.

You might be interested in

A box of coins contains nickels, dimes and quarters. The value of the coins is $4.00. If there were 3 times as many nickels, hal

frez [133]

Step-by-step explanation:

s ks ok w merto s mak osmwokwmsos

8 0

2 years ago

Read 2 more answers

Which of the following represents an equation of a line parallel to one whose equation is 2x + 8x = 18

Naya [18.7K]

Answer:

y=-4x+3

Step-by-step explanation:

it does not show the equations that are following

but the main thing you need to know is that when two lines are parallel they have the same slope

and do you mean 2x+8y=18 not x?

edit:

answer choices: y=-4x+3, y=8x-2, y=4x+7, y=-8x+9

2y+8x=18

first change that equation to slope intercept form to find the slope

2y = -8x+18 -> y = -4x+9

slope is -4

so the answer is y=-4x+3 because it also has a slope of -4

5 0

2 years ago

(csc x - 1) (csc x + 1)

victus00 [196]

<h2>Explanation:</h2>

Here we have the following expression:

$(csc x - 1) (csc x + 1)$

So we need to extend this. Remember that the difference of squares tells us:

$(a-b)(a+b)=a^2-b^2$

So here:

$a=cscx \\ \\ b=1$

Thus:

$(csc x - 1) (csc x + 1)=csc^2x-1 \\ \\ \\ But: \\ \\ cscx=\frac{1}{sinx} \\ \\ \\ Then: \\ \\ csc^2x-1=\frac{1}{sin^2x}-1=\frac{1-sin^2x}{sin^2x}=\frac{cos^2x}{sin^2x}=cot^2x \\ \\ \\ Finally: \\ \\ \boxed{(csc x - 1) (csc x + 1)=cot^2x}$

4 0

3 years ago

36 (6 - 4x) – 27x = 10x - 31

Colt1911 [192]

The answer is highlighted and I put the work for checking the answer at the bottom

4 0

3 years ago

For mutually exclusive events we can use the ____ Principle of Counting.

leonid [27]

Fundamental principle of counting

5 0

2 years ago