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aleksandr82 [10.1K]

2 years ago

6

What Number shoulgo in the box? 5979=5000+□+70+9

1 answer:

BabaBlast [244]2 years ago

8 0

Answer:

900

Step-by-step explanation:

5979 = 5000+70+9+□

5979 = 5079+□

5979-5079 = □

900 = □

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Find the focus.<br> x2 = 6y<br> A. (0, 3/2)<br> B. (0,6)<br> C. (0, -3/2)<br> D. (3/2,0)

IRISSAK [1]

Answer:

Step-by-step explanation:

its A

4 0

3 years ago

Write down the first three terms of the sequence whose nth term is given by 2n-5

likoan [24]

Answer:

- 3, - 1, 1

Step-by-step explanation:

To find the first 3 terms substitute n = 1, 2, 3 into the formula

a₁ = 2(1) - 5 = 2 - 5 = - 3

a₂ = 2(2) - 5 = 4 - 5 = - 1

a₃ = 2(3) - 5 = 6 - 5 = 1

The first 3 terms are - 3, - 1, 1

6 0

3 years ago

The inequality log8(2x) < log2(x – 2) can be graphed on the graphing calculator by using the inequalities log8(2x) < y and

denis-greek [22]

Answer:

c - (4, ∞)

Step-by-step explanation:

answer on edg

4 0

3 years ago

Arrange the entries of matrix A in increasing order of their cofactors values

givi [52]

To find the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

We cross out the Row and columns of the respective entries and find the determinant of the remaining $2\times 2$ matrix with the alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

7 0

3 years ago

Read 2 more answers

HELP! A S A P! ONLY ANSWER IF YOU'RE 100% SURE.

Sidana [21]

ANSWER

Three (3) cartons of juice

Y=3X+68.25

80=3X+68.25
Subtract 68.25 from both sides
11.75=3X

Divide

11.75/3=3.91
He can't buy a portion of a juice but he doesn't have enough to buy 4

So he can afford 3 juice cartons

6 0

3 years ago