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3 years ago

Evaluate the sine of angle X for the right triangle below.

Mathematics

1 answer:

bezimeni [28]3 years ago

6 0

Answer:

$\frac{7}{25}$

Step-by-step explanation:

sinx = $\frac{opposite}{hypotenuse}$

The hypotenuse = 25 since 7, 24, 25 ← Pythagorean triple

Hence

sinx = $\frac{7}{25}$

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Points B, O, Y are collinear on BY, and BO:OY=5/8. B is located at (4,2), O is located at (7, -3) and Y is located at (x,y). Det

Viktor [21]

Answer:

x = $\frac{59}{5}$

y = -11

Explanation:

Given that a line segment BY. O is the point lies between B & Y.

Ratio is BO:OY = 5:8

Coordinate of point B = (4,2)

Coordinate of point O = (7,-3)

We will find the coordinate of Y (x,y)

Here we use the section formula.

Internal section formula is :

$Y(x,y) =(\frac{mx_{2}+nx_{1}}{m + n},\frac{my_{2}+ny_{1}}{m + n})$

(7,-3) = $(\frac{5*x+8*4}{5+8} ,\frac{5*y+8*2}{5+8} )$

(7,-3) = $(\frac{5x+32}{13}, \frac{5y+16}{13})$

Now

7 = $\frac{5x+32}{13}$

5x+32 = 91

x = $\frac{59}{5}$

and

$-3 =\frac{5y+16}{13}$

5y + 16 = -39

y = -11

That's the final answer.

8 0

3 years ago

The owner of a triangle lot wishes to fence it along the lot lines. Lot markers at A and B have been located, but the lot marker

Allisa [31]

Answer: well it is um 49.8

Step-by-step explanation:

6 0

3 years ago

The Wind Mountain excavation site in New Mexico is an important archaeological location of the ancient Native American Anasazi c

timurjin [86]

Answer:

a) 28

Class Limits Class Boundaries Midpoint f Rf Cf

10 - 37 9.5-37.5 23.5 7 0.096 7

38 - 65 37.5-65.5 51.5 25 0.342 32

66 - 93 65.5-93.5 79.5 26 0.356 58

94 - 121 93.5-121.5 107.5 9 0.123 67

122 - 149 121.5-149.5 135.5 5 0.068 72

150 - 177 149.5-177.5 163.5 0 0.0 72

178 - 205 177.5-20.5 191.5 1 0.014 73

Total 73 1.0

The histogram is in attached file.

Step-by-step explanation:

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx

5 0

3 years ago

8 k+d use k=2 and d=3

sveta [45]

8×2=16

16+d

d=3

16+3=19

5 0

3 years ago

What is the solution to the equation -4 (2x + 3) = 2x + 6 - (8x + 2)

jeka94

Answer:

x= -8 i believe

Step-by-step explanation:

4 0

2 years ago