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Masteriza [31]
4 years ago
15

Taxi company charges $ 8.00 to get into the cab and $ 0.75 per mile. Taxi company B charges $ 6.00 to get into a cab and $ 1.25

per mile. How many miles would the cost be the same for both companies?
help me ​
Mathematics
2 answers:
7nadin3 [17]4 years ago
5 0

Answer:

50 miles

Step-by-step explanation:

Let the miles traveled be x when cost for both taxi A and Taxi B is same

Lets calculate for Taxi A

charge to get in cab = $8

cost of traveling 1 mile = $ 0.75

cost of traveling for x miles = x * cost of traveling 1 mile= $ 0.75x

Total cost for traveling x miles = charge to get in cab +cost of traveling for x mile

Total cost for traveling x miles in Taxi A = $8 + $ 0.75x

______________________________________________

Lets calculate for Taxi B

charge to get in cab = $3

cost of traveling 1 mile = $ 1.25

cost of traveling for x miles = x * cost of traveling 1 mile= $ 1.25x

Total cost for traveling x miles = charge to get in cab +cost of traveling for x mile

Total cost for traveling x miles in Taxi B= $3 + $ 1.25x

As we have to find distance when cost for both is same

Thus

Total cost for traveling x miles in Taxi A=Total cost for traveling x miles in Taxi B

8 +  0.75x = 3 +  1.25x

8 - 3 = 1.25x -  0.75x

5 = 0.5x

x = 5/0.5 = 50

Thus, you must travel 50 miles so that cost in both the taxi A and Taxi B is the same

ELEN [110]4 years ago
5 0

Answer:4

Step-by-step explanation:

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