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olga2289 [7]
3 years ago
6

John must have at least 289 test points to pass his math class he already has test scores of 72, 78 and 70 which inequality will

tell him at least how many more points he need to pass the class
Mathematics
2 answers:
WITCHER [35]3 years ago
8 0
He has 220 total so he needs x, as long as
x≥69
max2010maxim [7]3 years ago
5 0

Hello!

First of all, let's see how many total points he already has.

72+78+70=220

This means he needs at least 69 points. This gives us the inequality below.

x≥69

I hope this helps!

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Martin charges $15 for every 5 bags of leaves he rakes. Last weekend, he raked 27 bags of leaves. How much money did he earn?
Burka [1]
Set up a proportion and then cross multiply to solve. OR. 15/5 = $3 per bag is the unit rate per 1 bag.
Multiply 27*3=$81
8 0
4 years ago
Read 2 more answers
Expand the single bracket <br> 12(b +3)
Sunny_sXe [5.5K]

Answer:

12b + 36

Step-by-step explanation:

multiply the outside of the bracket by the inside

12(b + 3)

12b + 36

8 0
3 years ago
Stevie Baker received 15 kg 700 g of sugar. The production manger noticed that they needed 23 kg 100 g of sugar to make the orde
Tju [1.3M]

Answer:

She need <u>7 kg 400 g</u> of sugar more to complete this order of cookies.

Step-by-step explanation:

Given:

Stevie Baker received 15 kg 700 g of sugar. The production manager noticed that they needed 23 kg 100 g of sugar to make the order of cookies she just received.

Now, to find the quantity of sugar she need to complete this order of cookies.

Quantity of sugar Stevie Baker received = 15 kg 700 g.

Quantity of sugar needed to make the order = 23 kg 100 g.

Now, to get the quantity of sugar she need to complete this order of cookies we subtract quantity of sugar Stevie Baker received  from quantity of sugar needed to make the order:

23\ kg\ 100\ g-15\ kg\ 700\ g

=7\ kg\ 400\ g.

Therefore, she need 7 kg 400 g of sugar more to complete this order of cookies.

4 0
3 years ago
Two shirt screening companies charge a set up fee and a charge for each shirt made.
lara31 [8.8K]

Answer:

The correct option is;

Shirt Express charges less per shirt. For the cost to be the same 74 shirts must be ordered

Step-by-step explanation:

1) The given table for Shirt Express can be used to find the equation of the total cost of each made by Shirt Express as follows;

The rate of change of the function m is given as follows;

m = \dfrac{y_2 - y_1 }{x_2 - x_1}

Therefore, we have;

m = (438 - 353)/(50 - 40) = 8.5

Te equation in slope and intercept form is then y - 438 = 8.5(x - 50)

From which we have;

y = 8.5·x - 8.5×50 + 438 = 8.5·x + 13

y = 8.5·x + 13

Therefore, Shirt Express initially charges 13 per shirt which is less than the 50 Shirt Custom charges

2)  the cost to be the same, we equate both shirts equations to get;

8.5·x + 13 = 8·x + 50

0.5·x = 50 - 13 = 37

x = 37/0.5 = 74 shirts

Therefore, for the cost to be the same 78 shirts must be ordered

4 0
3 years ago
Find set<br> A={1, 2, 6, 10}<br> B={3, 6, 9, 10, 11}<br> C = {1, 2, 4, 7, 11}
PilotLPTM [1.2K]

If <em>U</em> = {1, 2, 3, …, 12} is the universal set, and

<em>A</em> = {1, 2, 6, 10}

<em>B</em> = {3, 6, 9, 10, 11}

<em>C</em> = {1, 2, 4, 7, 11}

then

(1) <em>A</em> U <em>B</em> is the set containing all elements from <em>A</em> and <em>B</em>,

<em>A</em> U <em>B</em> = {1, 2, 3, 6, 9, 10, 11}

(2) <em>A</em> ∩ <em>B</em> is the set of elements that are contained in both <em>A</em> and <em>B</em>,

<em>A</em> ∩ <em>B</em> = {6, 10}

(3) Unfortunately, <em>A</em> ∩ <em>B</em> U <em>C</em> is somewhat ambiguous. It could mean (<em>A</em> ∩ <em>B</em>) U <em>C</em> or <em>A</em> ∩ (<em>B</em> U <em>C </em>). Then either

(<em>A</em> ∩ <em>B</em>) U <em>C</em> = {6, 10} U {1, 2, 4, 7, 11} = {1, 2, 4, 6, 7, 10, 11}

or

<em>A</em> ∩ (<em>B</em> U <em>C </em>) = {1, 2, 6, 10} ∩ {1, 2, 3, 4, 6, 7, 9, 10, 11} = {1, 2, 6, 10}

The first interpretation is probably the intended one, since that essentially reads the set operations from left to right.

(4) <em>A'</em> U <em>B</em> is the union of <em>A'</em> and <em>B</em>, where <em>A'</em> is the complement of <em>A</em>, or all elements in <em>U</em> that are not in <em>A</em>. We have

<em>A'</em> = <em>U</em> - <em>A</em> = {3, 4, 5, 7, 8, 9, 11, 12}

and so

<em>A'</em> U <em>B</em> = {3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

(5) We have

<em>A</em> U <em>C</em> = {1, 2, 4, 6, 7, 10, 11}

so that

(<em>A</em> U <em>C </em>)<em>'</em> = <em>U</em> - (<em>A</em> U <em>C</em> ) = {3, 5, 8, 9, 12}

(6) We have

<em>B'</em> = <em>U</em> - <em>B</em> = {1, 2, 4, 5, 7, 8, 12}

and so

<em>A</em> ∩ <em>B'</em> = {1, 2}

(7) Using the complements found in (4) and (6), we have

<em>A'</em> U <em>B'</em> = {1, 2, 3, 4, 5, 7, 8, 9, 11, 12}

Alternatively, we can use the fact that

<em>A'</em> U <em>B'</em> = (<em>A</em> ∩ <em>B</em>)<em>'</em>

and since we know from (2) that <em>A</em> ∩ <em>B</em> = {6, 10}, we end up with the same result,

(<em>A</em> ∩ <em>B</em>)<em>'</em> = <em>U</em> - (<em>A</em> ∩ <em>B</em>) = {1, 2, 3, 4, 5, 7, 8, 9, 11, 12}

(8) We have

<em>A</em> U <em>B</em> U <em>C</em> = {1, 2, 3, 4, 6, 7, 9, 10, 11}

so that

(<em>A</em> U <em>B</em> U <em>C</em> )<em>'</em> = {5, 8, 12}

6 0
3 years ago
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