Question

Of the 200 students surveyed at the local high school, 126 say that they prefer earlier start times for school. What is the mean of the sampling distribution of the proportion of the students who prefer later start times for school

Answer 1

Answer:

The mean of sampling distribution of the proportion of the students who prefer later start times for school

                        μₓ = p = 0.63

Step-by-step explanation:

Explanation:-

Given sample size 'n' =200

given data Of the 200 students surveyed at the local high school, 126 say that they prefer earlier start times for school

sample proportion

                        $p = \frac{x}{n} = \frac{126}{200} = 0.63$

The mean of sampling distribution of the proportion of the students who prefer later start times for school

                        μₓ = p = 0.63

Standard deviation of the proportion

                     $S.D = \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.63(1-0.63)}{200} } = 0.034$