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Naddika [18.5K]
3 years ago
8

(01.03)

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0
The dimensions of the paint tray are:
W = 10 in
L = 12 in
D = 5 cm (1in / 2.54 cm) = 1.97 in

The total volume of the paint tray is:
Vt = WLD
Vt = (10)(12)(1.97) = 236.22 in3

Converting the volume of the paint to in3
Vp = 1 gal (231 in3 / 1gal) = 231 in3

Getting the difference,
236.22 in3 - 231in3 = 5.22 in3

Since the volume of tray is greater than the volume of the paint, the answer is:
The paint will not fill the tray by 5.22 in3.
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Given △ABC. m∠A>m∠B>m∠C. Perimeter=30. Which side of △ABC may have length 7?
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As given in △ABC,

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As from the properties of trigonometry we know that, the greater the angle is, the greater is the value of its sine. i.e

\sin A>\sin B>\sin C

According to the sine law,

\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}

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Also given that its perimeter is 30. Now we have to find out whose side length is 7. So we have 3 cases.

Case-1. Length of a is 7

As a must be the greatest, so b and c must be less than 7. Which leads to a condition where its perimeter won't be 30. As no 3 numbers less than 7 can add up to 30.

Case-2. Length of b is 7

As b is greater than c, so c must 6 or less than 6. But in this case the formation of triangle is impossible. Because the triangle inequality theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side. If b is 7 and c is 6, then a must be 17. So no 2 numbers below 7 can add up to 17.

Case-3. Length of c is 7

As this is the last case, this must be true.

Therefore, by taking the aid of process of elimination, we can deduce that side c may have length 7.


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