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3 years ago

(01.03)

1 answer:

6 0

The dimensions of the paint tray are:
W = 10 in
L = 12 in
D = 5 cm (1in / 2.54 cm) = 1.97 in

The total volume of the paint tray is:
Vt = WLD
Vt = (10)(12)(1.97) = 236.22 in3

Converting the volume of the paint to in3
Vp = 1 gal (231 in3 / 1gal) = 231 in3

Getting the difference,
236.22 in3 - 231in3 = 5.22 in3

Since the volume of tray is greater than the volume of the paint, the answer is:
The paint will not fill the tray by 5.22 in3.

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Sven can type 30 words per minute.How many words would he type in 20 minutes?

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Gnom [1K]

Answer:

Width=28 1/3 Length=51 2/3

Step-by-step explanation:

1. Create an equation

x+(2x-5)=80

2. Solve

x+(2x-5)=80

3x-5=80

3x-5+5=80+5

3x/3=85/3

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So, if x=28 1/3

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3 years ago

Trisha and Byron are washing and vacuuming cars to raise money for a class trip. Trisha raised $38 washington 5 cars and vacuumi

ANEK [815]

Answer:

They charged $6 for washing and $2 for vacuuming the car.

Step-by-step explanation:

Let the charge of washing a car be 'x'.

And also let the charge of vacuuming a car be 'y'.

Now according to question, Trisha raised $38 washing 5 cars and vacuuming 4 cars.

So framing the above sentence in equation form, we get;

$5x+4y=38\ \ \ \ \ equation\ 1$

Again according to question, Byron raises $28 by washing 4 cars and vacuuming 2 cars.

So framing the above sentence in equation form, we get;

$4x+2y=28\ \ \ \ \ equation\2$

Now multiplying equation 2 by '2', we get;

$2(4x+2y)=28\times2\\\\8x+4y=56\ \ \ \ equation\ 3$

Now we subtract equation 1 from equation 3 and get;

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Now substituting the value of 'x' in equation 1, we get;

$5x+4y=38\\\\5\times6+4y=38\\\\30+4y=38\\\\4y=38-30=8\\\\y=\frac{8}{4}=2$

Hence They charged $6 for washing and $2 for vacuuming the car.

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3 years ago

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MAXImum [283]

Answer:

√36 = 6

a^2 + b^2 = c^2

6^2 + 6^2 = c^2

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72 = c^2

√72 = c

2 36

2 18

2 9

3 3

6√2 = c

6√2 = (estimate rounded up, 8.49)

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Ivahew [28]

Answer:

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Step-by-step explanation:

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