Answer: a< -4 D
Step-by-step explanation:
Step-by-step explanation:
here ,
length = 8m
height=4m
Rate of plastering 4 walls = 15/m^2
Cost of plastering 4 wall = Rs 1560
Area of floor = Cost of plastering / Rate of plastering
= 1560/15
= 104
again,
Area of four wall = 2h(l+b)
or, 104= 2×4(8+b)
or, 104 =8(8+b)
or, 104/8=8+ b
or,13 - 8= b
or, b= 5
again,
Area of floor= l×b
= 8×5
= 40
again,
Rate of carpeting the floor= 300/ m^2
Area of floor = 40 m^2
cost of carpeting=Rate × Area
= 300×40
= 12000
Answer:
Option A
Step-by-step explanation:
Given that A linear model is given for the data in the table: y=1.25x+2.
Let us write observed values for each x and also the predicted values as per equation.
x 2 3 4 8 10 16 20 24 Total
y((O) 3 4 7 12 16 22 28 30
y(P) 4.5 5.75 7 12 14.5 22 27 32
DEv 1.5 1.75 0 0 1.5 0 1 2 7 75
where y(0) represents observed y or y in the table given
y(P) gives values of y predicted as per the equation 1.25x+2
Dev represents the absolute difference
Hence answer is option
A.7.75
Answer: seven hundred thousand
