What is bacteria in meters? Give answer in scientific notation show work plz&ty

The perimeter of a rectangle is 128 inches.

Anuta_ua [19.1K]

Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.

<h3>What is the perimeter of a rectangle?</h3>

The perimeter of a rectangle of length l and width w is given as follows:

P = 2(l + w).

The length is an odd integer and the width is 5 times the next consecutive odd integer, hence:

l = x, w = 5(x + 2).

The perimeter is of 128 inches, hence:

128 = 2l + 2w

128 = 2x + 10(x + 2)

128 = 2x + 10x + 20

12x = 108

x = 9.

Hence the length is of 9 inches and the width is of 55 inches.

More can be learned about the perimeter of a rectangle at brainly.com/question/10489198

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6 0

1 year ago

50× 3/8 how to reduce answer to lowest te

hoa [83]

The lowest term is $\frac{75}{4}$ .

Solution:

Given expression is $50\times\frac{3}{8}$

To reduce this term to the lowest term:

$$50\times\frac{3}{8}=\frac{50}{1}\times\frac{3}{8}$

Multiply the numerator and denominator.

$$50\times\frac{3}{8}=\frac{150}{8}$

Now, divide the numerator and denominator by the greatest common factor.

Here 150 and 8 both have common factor 2.

So, divide numerator and denominator by 2.

$$=\frac{150\div2}{8\div2}$

$$=\frac{75}{4}$

$$50\times\frac{3}{8}=\frac{75}{4}$

Hence the lowest term is $\frac{75}{4}$ .

4 0

3 years ago

What is the perimeter of this polygon? (2, 4) (-1,2) (3,-2) (-2,-3)

Ber [7]

Answer:

I think the answer is 19

Step-by-step explanation:

7 0

3 years ago

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

3 years ago

I need help to solve please

antiseptic1488 [7]

Answer:

Step-by-step explanation:

Known:

What to find = x

Exterior angle = 142

Right angle = 90

Unknown:

what unknown value is = ?

Interior angle = ?

1. Find the angle of the interior angles.

180 - 142 = 38

2. Add the two known angles

38 + 90 = 128

3. Subtract from 180

180 - 128 = 52

<h2>x = 52 is the answer.</h2>

Hope this helped,

Kavitha Banarjee

6 0

3 years ago