A farmer wants to mow two rectangular garden of dimensions 14 m × 12 m and 15m × 10m. Find the cost of mowing both the gardens a
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Answer:
The <u>MEDIAN</u>, <u>4.5</u> hours, is the best measure of center, so the <u>IQR</u> is the best measure of variability.
McKennas conclusion <u>IS NOT</u> accurate. The mode of her data <u>IS</u> 6 hours. However, <u>MORE</u> than half of the time, she spends <u>LESS</u> than 6 hours riding her horse. It would be more accurate to say that Mckenna typically rides her horse between <u>2.5</u> and 6 hours.
Step-by-step explanation:
Put the values in order of smallest to largest:
0, 2, 2, 2.5, 2.5, 3, 4, 5, 6, 6, 6, 8, 9, 10
Median (middle value) = (4 + 5)/2 = 4.5
Lower quartile Q1 = 2.5
Upper quartlie Q3 = 6
IQR = Q3 - Q1 = 3.5
Mode (value that occurs most often) = 6
Mean (average) = sum of values ÷ number of values = 4.7
Range (difference between the highest and lowest values) = 10 - 0 = 10
Median is the best measure of the center since it isn't influenced by extreme values.
IQR is less affected by outliers and extreme values. It gives a consistent measure of variability for skewed data.
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The <u>MEDIAN</u>, <u>4.5</u> hours, is the best measure of center, so the <u>IQR</u> is the best measure of variability.
McKennas conclusion <u>IS NOT</u> accurate. The mode of her data <u>IS</u> 6 hours. However, <u>MORE</u> than half of the time, she spends <u>LESS</u> than 6 hours riding her horse. It would be more accurate to say that Mckenna typically rides her horse between <u>2.5</u> and 6 hours.
