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3 years ago

What will go Inside the boxes?

Mathematics

1 answer:

e-lub [12.9K]3 years ago

8 0

Answer:

18500 is the initial value

Every year they increase by a factor of 1.03

Step-by-step explanation:

This is written in the form

y = ab^x where a is the initial value and b is the growth rate/decrease

y = (18500) (1.03)^t

The initial value is 18500

The students will increase by 1.03 - 1 = .03

The factor of increase is what they multiply by which is 1.03

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The ratio of clown fish to angel fish at a pet store is 5:4 . The ratio of angel fish to gold fish is 4:3. There are 60 clown fi

SVEN [57.7K]

A) 60 Clown fish / 5 = 12
12 x 4 = 28 Angel fish
B) 28 Angel fish / 4 = 12
12 x 3 = 36 Gold fish
C) Add all fish 28 Angel fish + 36 Gold fish + 60 Clown fish = 124 Fish in total

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3 years ago

If x varies directly with y and x = 3.5 when y = 14, find x when y = 18.

maks197457 [2]

Answer:

x = 4.5

Step-by-step explanation:

there's definitely other ways to solve this, but I used a proportion.

$\frac{3.5}{x} = \frac{14}{18}$

Then you can make this equation:

14x = 3.5 * 18

I solved for it and got 4.5 .

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3 years ago

How many presents are between 40_45 years old

elena-14-01-66 [18.8K]

The answer would be 2 hope this helps

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2 years ago

Read 2 more answers

On any given day, mail gets delivered by either Alice or Bob. If Alice delivers it, which happens with probability 1/4 , she doe

Troyanec [42]

Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let X denote delivery time of the mail delivered by Alice and Y denote delivery time of the mail delivered by Bob.

It i provided that:

$X\sim U(9, 11)\\Y\sim U(10, 12)$

The probability that Alice delivers the mail is, p = 1/4.

The probability that Bob delivers the mail is, q = 3/4.

The probability density function of a Uniform distribution with parameters [a, b] is:

$f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Alice is:

$f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Bob is:

$f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.$

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

$f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125$

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

$f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50$

Thus, the value of fₓ (10.5) is 0.50.

5 0

3 years ago

Which is greater -0.25 or 0.8

GrogVix [38]

0.8 is greater because it is a positive number..

5 0

3 years ago

Read 2 more answers