9514 1404 393
Answer:
A. no solution
B. unique solution: (x, y) = (0, 0)
Step-by-step explanation:
For these problems, you can subtract the second equation from the first to get something of the form ...
0 = (expression)
The solution of that will tell you the answer.
__
A. (2x +3y) -(2x +3y) = (4) -(9)
0 = -5 . . . . . . . . no values of x or y will make this true: NO SOLUTION
__
B. (y) -(y) = (6x) -(x)
0 = 5x
0 = x . . . . . . divide by the coefficient of x.
y = x = 0
The unique solution is (x, y) = (0, 0).
Answer:
50%
Step-by-step explanation:
7 nurses
3 doctors
4 offices
14 in total
7/14 or 50% is the probability
Answer:
I dont see a question.
Step-by-step explanation:
Answer:
32 cm by 18 cm
16 cm by 36 cm,
48 cm by 12 cm
24 cm by 24 cm
Step-by-step explanation:
<u><em>The complete question is</em></u>
A boy wants to build rectangular cages. He wants all the sides on the base of his cages to beat least 10 cm long.he also wants the base area to equal 576 cm2. The boy needs help to find all the possible lengths and widths for the base of the cages. He used only whole centimeters, with no fractional parts.what are all the possible dimensions for the rectangular base?
we know that
The number 576 decompose in prime factors is the same that write
To find out possible side lengths, multiply different combinations of these prime numbers together (make sure each pair adds up to 10)
3x3=9cm 2x2x2x2x2x2= 64cm ----> is not a combination (one side is not greater than 10)
3x3x2= 18cm 2x2x2x2x2= 32cm
3x3x2x2= 36cm 2x2x2x2= 16cm
3x2x2= 12cm 3x2x2x2x2= 48cm
3x2x2x2= 24cm 3x2x2x2= 24cm
therefore
32 cm by 18 cm
16 cm by 36 cm,
48 cm by 12 cm
24 cm by 24 cm
Answer:
(1 ) Inner curved surface area of the well is 109.9 sq. meters.
(2) The cost of plastering the total curved surface area is 4396.
Step-by-step explanation:
The inner diameter = 3.5 m
Depth of the well = 10 m
Now, Diameter = 2 x Radius
⇒R = D/ 2 = 3.5/2 = 1.75
or, the inner radius of the well = 1.75 m
CURVED SURFACE AREA of cylinder = 2πr h
⇒The inner curved surface area = 2πr h = 2 ( 3.14) (1.75)(10)
= 109 sq. meters
Hence, the inner curved surface area of the well is 109.9 sq. meters.
Now, the cost of plastering the curved area is 40 per sq meters
So, the cost of total plastering total area = 109.9 x(Cost per meter sq.)
= 109.9 x (40)
= 4396
Hence, the cost of plastering the total curved surface area is 4396.
