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ser-zykov [4K]
2 years ago
8

Find the measure of the missing angle

Mathematics
1 answer:
Leokris [45]2 years ago
6 0

Answer:

z = 69°

Step-by-step explanation:

The sum of all interior angles in a quadrilateral is 360°, and a right angle is worth 90°. We're given the values of the interior angles as 90, 122, 79, and z degrees.

  • We can solve this question algebraically with the equation 90 + 122 + 79 + z = 360

Step 1: Combine like terms.

  • (90+122+79)+z=360
  • z + 291 = 360

Step 2: Subtract 291 from both sides.

  • z + 291 - 291 = 360 - 291
  • z = 69

Step 3: Check if solution is correct.

  • (69) + 261=360
  • 360 = 360

Therefore, z = 69°.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

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4 x 1 + 1 x 1/100 + 9 x 1/1000 in standard form
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let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a
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(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

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for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) =  y = 0(x) + 1(y)

Matrix Representation of T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]

now, eigen value of 'T'

T - kI =  \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

#SPJ4

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