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3 years ago

P, Q, R and S are four points on a circle.

Mathematics

1 answer:

shtirl [24]3 years ago

4 0

Answer:

Triangle PTS is an equilateral triangle because all sides are equal lengths.

Angle TPS and angle TSP are equal because it is an equilateral triangle.

Triangle PQS and triangle SRP are congruent because of the side-angle-side theorem.

Segment PQ is congruent to segment SR because congruent sides of congruent triangles are congruent.

Segment PR is congruent to segment SQ because congruent sides of congruent triangles are congruent.

Triangle PQR and triangle SRQ are congruent because of the side-side-side theorem.

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Verify sin^4x − sin^2x = cos^4x − cos^2x is an identity

Inga [223]

Answer:

<h2>It's an identity</h2>

Step-by-step explanation:

$\sin^4x-\sin^2x=\cos^4x-\cos^2x\\\\L_s=\sin^4x-\sin^2x=\sin^2x(\sin^2x-1)=\sin^2x(-\cos^2x)=-\sin^2x\cos^2x\\\\R_s=\cos^4x-\cos^2x=\cos^2x(\cos^2x-1)=\cos^2x(-\sin^2x)=-\sin^2x\cos^2x\\\\L_s=R_s\qquad\bold{CORRECT}$

$\text{Used:}\\\\\sin^2x+\cos^2x=1\Rightarrow\left\{\begin{array}{ccc}\cos^2x=1-\sin^2x\\\sin^2x=1-\cos^2x\end{array}\right\Rightarrow\left\{\begin{array}{ccc}-\cos^2x=\sin^2x-1\\-\sin^2x=\cos^2x-1\end{array}\right$

4 0

3 years ago

Read 2 more answers

Point G is on line segment FH. Given FH = 5x + 2, GH = 5x – 9, and

Anni [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

A person crosses a 600m long street in 5 mins. What is his speed in km per hr?

muminat

His speed would be 2 km/hr.
Where S is speed, D is distance, and T is time, the equation "S=D/T" can be applied. You would substitute the information provided in this equation. However, since the time is in minutes but your answer must be in km per HOUR, you must convert it.
S=D/T
There is 60 minutes in an hour, so you would substitute 5/60 for T.
S=600km/5/60
S=2km/hr

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4 years ago

Please help<br><br> 0.06/1.71

vredina [299]

Answer:

0.04

Step-by-step explanation:

0.03508772

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2 years ago

Show solving steps for x^2-10x +4=12

Nadya [2.5K]

Answer:

Step-by-step explanation:

We are given

$x^2 - 10x + 4 = 12\\$

get it all to one side equaling zero

$x^2 - 10x - 8 = 0$

now, we want to find the factors of 8 that either add up to of have a difference of 10

Factors of 8:

$1, 8, 2, 4$

None of the factor pairs add up to or have a difference of 10.

So, we can use the quadratic formula

$x = \frac{-b\pm\sqrt{b^2-4ac} }{2a} \\x = \frac{10\pm\sqrt{100-4*8} }{2}\\x = \frac{10\pm\sqrt{132} }{2}\\\\\\x = \frac{10 + \sqrt{132} }{2}= 10.74456265\\x = \frac{10 - \sqrt{132} }{2} = -0.7445626465$

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3 years ago