Let x represent the # of 2-hour days and y the # of 3-hour days. Jimmy's study was spread over 10 days. Thus, x + y must sum up to 10. Also, 2x + 3y must sum up to 22 hours.Our system now looks like this:
x + y = 10
2x + 3y = 22
Multiply the first equation by -2: -2x - 2y = -20 Add the 2nd equation to this:
-2x - 2y = -20
2x + 3y = 22
------------------ y = 2 So Jimmy had 2 3-hour study days and 8 2-hour study days.
Note how these figures add up to 22: 6 + 16 = 22
Hope that help!
(2x^2/(1-x^2)) + 3^(1/x) for the first half you can simply divide all terms by the highest power of x to get:
2/(1/x^2-1) as x approaches infinity you have 2/-1=-2
For the second part the exponent approaches zero as x approaches infinity and anything raised to the zero power is equal to 1 so you have:
-2+1=-1
So the limit as x approaches infinity is -1.
The number of costumes she can alter in four and a half hours is 18 customes.
<h3>How to calculate the number of custome?</h3>
From the information, the number of costumes she can alter varies directly with the amount of time spent working.
Since Belinda can alter four costumes in one hour, let the number of costumes she can alter in four and a half hours be represented by x.
This will be:
1/4 = 4.5/x
Cross multiply
x = 4.5 × 4.
x = 18
The number is 18.
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8+7+5= 20. The only color that is not red or blue is yellow. There are 8 yellows out of 20 cubes. The probability of selecting a cube at random that will not be blue or red is 8/20
Answer:
15/4
Step-by-step explanation:
4w+12=-3
4w=-15
w
=-15/4
