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3 years ago

PLEASE HELP LAST ONE

Mathematics

1 answer:

Damm [24]3 years ago

5 0

Answer:

please the answer is C which is; x is about 4•0 and y is about 14•6

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Just need the answer guys please

Mkey [24]

The first problem’s answer is true. (P.S. If you don’t understand this type of problems then plug in variables for them. It helps check your answer and solve them too.)

The second problem’s answer is false.

First of all, I plugged in for the variable a to be 6 for the first problem. Second, I plugged in numbers for the variables and x was 5 and x was 2 for the second problem. You can check the steps in the image I took. (P.S. You can use the MathPapa calculator online to solve these problems and plug in the variables.)

(I couldn’t upload the second problem’s step by step sorry, but if you need it then just use the MathPapa calculator by plugging in numbers for the variables.)

5 0

4 years ago

Can you help thank you i will give branlyist if you are correctt

seropon [69]

Answer:

The answer is: Y is always 2

Step-by-step explanation:

You can see this because as you go left to right the y corrodinate will always be 2 as the x increases/ decreases.

6 0

3 years ago

The length of a string between a kite and a point on the ground is 90 m. If

lorasvet [3.4K]

Answer:

79.4 m

Step-by-step explanation:

In this problem we deal with a right triangle with hypotenuse 90 m. We are told that tan Ф = 15/8; 15 represents the vertical distance of the kite off the ground and 8 represents the horizontal distance from the kite flyer to the kite. This is sufficient info from which to determine the angle of elevation from kite flyer to kite: tan Ф = 15/8 yields Ф = 1.08 radians.

Using this same angle Ф = 1.08 radians, sin Ф = (vertical distance) / hypotenuse = sin 1.08 rad = 0.882.

Then the vertical distance (height of the kite) is

(90 m)(0.882) = 79.4 m

8 0

3 years ago

Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

$T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326$

What is the probability that they are both queens?

$P = \frac{D}{T} = \frac{6}{1326} = 0.0045$

0.45% probability that they are both queens.

4 0

3 years ago

Write an algebraic expression for 8 less than 4 times a number

Flura [38]

Answer:

8<4*X

Step-by-step explanation:

8 less than is 8< the 4 times 4* a number so a variable, X

PLZ MARK ME AS BRAINIEST!

4 0

3 years ago