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Elenna [48]
4 years ago
13

What is not dead in science ?

Chemistry
1 answer:
Shalnov [3]4 years ago
6 0
Anything that is organic comes from Biological "LIFE" therefore unless something is inorganic like a rock then pretty much everything is living
You might be interested in
Carbon disulfide, CS2, can be made from coke, C(s), and sulfur dioxide, SO2(g). C(s) + SO2(g) à CS2(s) + CO2(g) If the actual yi
Virty [35]

Answer:

450g of coke (C)

Explanation:

Step 1:

The balanced equation for the reaction is given below:

3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)

Step 2:

Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.

This is illustrated below:

Molar Mass of C = 12g/mol

Mass of C from the balanced equation = 3 x 12 = 36g

Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Step 3:

Determination of the mass of C required to produce 950g of CS2. This is illustrated below:

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Therefore, Xg of C will react to produce 950g of CS2 i.e

Xg of C = (36 x 950)/76

Xg of C = 450g

From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.

6 0
3 years ago
The concentration of glucose, C6H12O6, in normal spinal fluid is 75 mg/100g. What is the molality of the solution
galben [10]

Answer:

4.16x10⁻³m

Explanation:

Molality is defined as the ratio between moles of a solute, in this case glucose, and kg of solvent.

As there are 100g of solvent, <em>the kg are 0.1. </em>Thus, we only need to calculate from the mass of glucose its moles to solve the molality of the solution.

<em>Moles glucose:</em>

There are 75mg = 0.075g of glucose. To conver mass to moles it is necessary molar mass.

Molar mass glucose:

6C = 12.01g/mol*6 = 72.06g/mol

12H = 12*1.008g/mol = 12.10g/mol

6O = 6*16g/mol = 96g/mol

72.06 + 12.10 + 96 = 180.16g/mol

Moles of 0.075g of glucose:

0.075g * (1 mol / 180.16g) =

4.16x10⁻⁴ moles of glucose

<em>Molality of the solution:</em>

4.16x10⁻⁴ moles of glucose / 0.1kg of solvent =

<h3>4.16x10⁻³m</h3>

7 0
4 years ago
One solution has a formula C (n) H (2n) O (n) If this material weighs 288 grams, dissolves in weight 90 grams, the solution will
saw5 [17]

Explanation:

The given data is as follows.

Boiling point of water (T^{o}_{b}) = 100^{o}C = (100 + 273) K = 323 K,

Boiling point of solution (T_{b}) = 101.24^{o}C = (101.24 + 273) K = 374.24 K

Hence, change in temperature will be calculated as follows.

              \Delta T_{b} = (T_{b} - T^{o}_{b})

                           = 374.24 K - 323 K

                           = 1.24 K

As molality is defined as the moles of solute present in kg of solvent.

            Molality = \frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}

Let molar mass of the solute is x grams.

Therefore,   Molality = \frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}

                        m = \frac{288 g \times 1000}{x g \times 90}              

                          = \frac{3200}{x}

As,    \Delta T_{b} = k_{b} \times molality

                 1.24 = 0.512 ^{o}C/m \times \frac{3200}{x}

                       x = \frac{0.512 ^{o}C/m \times 3200}{1.24}

                          = 1321.29 g

This means that the molar mass of the given compound is 1321.29 g.

It is given that molecular formula is C_{n}H_{2n}O_{n}.

As, its empirical formula is CH_{2}O and mass is 30 g/mol. Hence, calculate the value of n as follows.

                n = \frac{\text{Molecular mass}}{\text{Empirical mass}}

                   = \frac{1321.29 g}{30 g/mol}

                   = 44 mol

Thus, we can conclude that the formula of given material is C_{44}H_{88}O_{44}.

4 0
3 years ago
In which pair of elements are the chemical properties of the elements most similar?
trasher [3.6K]
Maybe isotopes but if you need a name isotopes of carbon because their number of electrons remains unchanged
8 0
4 years ago
A mole of gas at 0.0oC and 760. torr occupies 22.4 L. What is the volume of this gas at 25.oC and 760. torr
Solnce55 [7]

Answer:

24.45 L

Explanation:

From General gas equation,

PV/T = P'V'/T'.................... Equation 1

Where P = initial pressure, V = Initial volume, T = Initial Temperature, P' = Final pressure, V' = Final Volume, T' = Final Temperature.

make V' the subject of the equation.

V' = PVT'/(TP')................. Equation 2

Given: P = 760 torr, V = 22.4 L, T = 0 °C = (0+273) = 273 K, T' = 25 °C = (25 + 273) = 298 K, P' = 760 torr

Substitute into equation 2

V' = 760(22.4)(298)/(760×273)

V' = 24.45 L.

Hence the volume of the gas = 24.45 L

5 0
3 years ago
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