Answer:
450g of coke (C)
Explanation:
Step 1:
The balanced equation for the reaction is given below:
3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)
Step 2:
Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.
This is illustrated below:
Molar Mass of C = 12g/mol
Mass of C from the balanced equation = 3 x 12 = 36g
Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Step 3:
Determination of the mass of C required to produce 950g of CS2. This is illustrated below:
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Therefore, Xg of C will react to produce 950g of CS2 i.e
Xg of C = (36 x 950)/76
Xg of C = 450g
From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.
Answer:
4.16x10⁻³m
Explanation:
Molality is defined as the ratio between moles of a solute, in this case glucose, and kg of solvent.
As there are 100g of solvent, <em>the kg are 0.1. </em>Thus, we only need to calculate from the mass of glucose its moles to solve the molality of the solution.
<em>Moles glucose:</em>
There are 75mg = 0.075g of glucose. To conver mass to moles it is necessary molar mass.
Molar mass glucose:
6C = 12.01g/mol*6 = 72.06g/mol
12H = 12*1.008g/mol = 12.10g/mol
6O = 6*16g/mol = 96g/mol
72.06 + 12.10 + 96 = 180.16g/mol
Moles of 0.075g of glucose:
0.075g * (1 mol / 180.16g) =
4.16x10⁻⁴ moles of glucose
<em>Molality of the solution:</em>
4.16x10⁻⁴ moles of glucose / 0.1kg of solvent =
<h3>4.16x10⁻³m</h3>
Explanation:
The given data is as follows.
Boiling point of water (
= (100 + 273) K = 323 K,
Boiling point of solution (
= (101.24 + 273) K = 374.24 K
Hence, change in temperature will be calculated as follows.

= 374.24 K - 323 K
= 1.24 K
As molality is defined as the moles of solute present in kg of solvent.
Molality = 
Let molar mass of the solute is x grams.
Therefore, Molality = 
m =
= 
As, 

x = 
= 1321.29 g
This means that the molar mass of the given compound is 1321.29 g.
It is given that molecular formula is
.
As, its empirical formula is
and mass is 30 g/mol. Hence, calculate the value of n as follows.
n = 
= 
= 44 mol
Thus, we can conclude that the formula of given material is
.
Maybe isotopes but if you need a name isotopes of carbon because their number of electrons remains unchanged
Answer:
24.45 L
Explanation:
From General gas equation,
PV/T = P'V'/T'.................... Equation 1
Where P = initial pressure, V = Initial volume, T = Initial Temperature, P' = Final pressure, V' = Final Volume, T' = Final Temperature.
make V' the subject of the equation.
V' = PVT'/(TP')................. Equation 2
Given: P = 760 torr, V = 22.4 L, T = 0 °C = (0+273) = 273 K, T' = 25 °C = (25 + 273) = 298 K, P' = 760 torr
Substitute into equation 2
V' = 760(22.4)(298)/(760×273)
V' = 24.45 L.
Hence the volume of the gas = 24.45 L