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GalinKa [24]
4 years ago
9

How many mL of 2.0 M KOH are necessary to neutralize 50 mL of 1 M HCl?

Chemistry
1 answer:
worty [1.4K]4 years ago
6 0

Answer:

25mL

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this can help you. Have a nice day!

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Based on the name, which substance is a covalent compound?
V125BC [204]
QUICK ANSWER

The name of the covalent compound N2O5 is dinitrogen pentoxide, more commonly known as nitrogen pentoxide. This covalent compound is part of a bigger group of compounds, nitrogen oxides, created purely from nitrogen and oxygen

6 0
3 years ago
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A gas occupies a volume of 2.4 L at 14.1 kPa. What volume will the gas occupy at 84.6 kPa?
Naddik [55]

Answer:

  • <u>0.40 L</u>

Explanation:

Boyle's law for gases states that, at constant temperature, the volume and pressure of a fixed amount of gas are inversely related.

Mathematically, that is:

  • PV = constant

  • P₁V₁ = P₂V₂

Here, you have:

  • V₁ = 2.4 L
  • P₁ = 14.1 Kpa
  • P₂ = 84.6 KPa
  • V₂ = ?

Then, you can solve for V₂:

  • V₂ = P₁V₁ / P₂

Substitute and compute:

  • V₂ = 14.1 KPa × 2.4L / 84.6 KPa = 0.40 L ← answer
3 0
3 years ago
Which way does equilibrium shift
Natali [406]
You can use Le Chatelier's Principle to describe the equilibrium shift.

Le Chaterlier's Principle states that: "<span>If a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change."

Thus, if you heat up the reaction, the equilibrium shift favors the endothermic reaction. If you increase pressure (if gases are involved), the shift favors the reaction that produces less gaseous products (to counteract pressure) and so on.</span>
8 0
3 years ago
I just need 4-8! Plz hurry!!!!!!!!!!!
RSB [31]

Answer:

4: 90N

5: 7.77777m/s

6: 4

7: 12.5609756098

8: 187.5

Explanation:

8 0
3 years ago
Urea, CO(NH2)2, is manufactured on a large scale for use in producing urea-formaldehyde plastics and as a fertilizer. What is th
Pachacha [2.7K]

Answer:

5.004kg

Explanation:

Combustion of carbon

C+O2=CO2

from the relationship of molar ratio

mass of carbon/molar mass of carbon=volume of CO2 produced\molar vol(22.4 dm3)

mass of carbon =1000kg

atomic mass of carbon =12

volume of CO2 produced=1000×22.4/12

volume of CO2 produced =1866.6dm3

from the combustion reaction equation provided

CO2 (g) + 2NH3 (g) ⟶ CO (NH2 )2 (s) + H2 O(l)

applying the same relationship of molar ratio

no of mole of CO2=no of mole of urea

therefore

vol of CO2\22.4=mass of urea/molar mass of urea

molar mass of urea=60.06g/mol

from the first calculation

vol of CO2=1866.6dm3

mass of urea=1866.6×60.06/22.4

mass of urea=5004.82kg

7 0
3 years ago
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