CaO + H2O → Ca(OH)2
the number of O atom on the left side is 1 and on the right side 2 so,
we put 2H2O instead of H2O
CaO + 2H2O → Ca(OH)2
now we have to put 2Ca(OH)2 instead of Ca(OH)2 to make H atoms equal on both sides 4
CaO + 2H2O → 2Ca(OH)2
now we have to put 2CaO instead of CaO to make Ca atoms equal on both sides 2 atoms.
∴ the final balanced equation is:
2CaO + 2H2O → 2 Ca(OH)2
∴ the coefficients are 2 2 2
so basically
some fuels have an impurity in them which is sulfur.
When the fuel undergoes combustion, the sulfur reacts with oxygen in the air to form sulfur dioxide.
the sulfur dioxide reacts with water vapour in the air to form sulfurous acid, which is a type of acid rain.
Also
the high pressures inside a car engine may cause nitrogen and oxygen in the air to react and form oxides of nitrogen. the most common compounds formed inside car engines are NO (nitrogen oxide) and NO2 (nitrogen dioxide)
<em>Answer:</em>
There are two major resonance contributors for the en-amine. One contributor have no formal charges, only have one lone pair at N while the other one has positive and negative formal charges.
<em>Explanation:</em>
An en-amine is formed by the condensation reactions of aldehydes or ketone with secondary amine.
The contributor<em> </em>I have no formal charges. It has only one lone pair at Nitrogen atom.
The contributor II has +1 formal charges at N, and -1 formal charges at α Carbon.
Please see attachment. The resonance contributor are given.
If a<span> student used 10 mL water instead of 30 mL for extraction of salt water from mixture, the extraction of salt will be lesser than compared to using 30 mL since less solute will dissolve in 10 mL.</span>
I can't explain the like dissolves like part but the water and oil I can
when oil is poured into water the oil will stay at the top of the water meaning that water is more dense than oil
