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3 years ago

11

dennis ran a mile in 593.7 seconds.martina ran a mile in 573.36 seconds. what was the difference in their running times? A-5.14

s B-6.01 C - 20.34 s D -26.01 s

2 answers:

Svetlanka [38]3 years ago

8 0

subtract them

593.7-573.36 = 20.34seconds

so c is the answer

harina [27]3 years ago

4 0

C- subtract Martina's from Dennis's.

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Which of the following is a radical equation?<br><br> X+ 5-12<br> x2 = 16<br> 3+ x7 - 13<br> X = 14

pogonyaev

None of those could be a radical, you would have to have a radical symbol for it to become a radical

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4 years ago

YOU RRR MEH HEROOOZZ! PUHLEASZEEE ITS 10:30pm!!

avanturin [10]

Answer:

$x(35)\approx 11.8$

Step-by-step explanation:

<u>Modeling With Functions </u>

We have a table of values of speeds vs distance taken for a car to stop. We are required to find a model that uses the square root and fits the given data to predict other values of d as a function of v.

By the nature of the problem, we can know that for v=0, d must be 0 too. So our model won't include a vertical shift or independent term. Being v the speed of the car and x the distance it takes to stop, we use the following model

$x(v)=A\sqrt{v}$

We must find A to make the function fit the data. Let's use the first point (v,x); (20,9)

$9=A\sqrt{20}$

Solving for A

$\displaystyle A=\frac{9}{\sqrt{20}}$

$A\approx 2$

Then we have

$x(v)=2\sqrt{v}$

Evaluating for v=35

$x(35)=2\sqrt{35}=11.83$

$\boxed{x(35)\approx 11.8}$

Last option

8 0

3 years ago

11,22,22,13,24,22 find the hunderds too

earnstyle [38]

Answer:

excuse me, but how do we answer this? This question is unanswerable without it being a question!

Step-by-step explanation:

5 0

3 years ago

Jobisdone [24]

Answer:

The light bulb will reach the ground 1.25 seconds after it is dropped.

Step-by-step explanation:

We know that for an object that is in the air, the only force acting on it will be the gravitational force (where we are ignoring the air resistance)

Then the acceleration of the object is the gravitational acceleration, 32.17 ft/s^2

Then the acceleration of the light bulb is:

A(t) = (-32.17 ft/s^2)

Where the negative sign is because the acceleration is downwards.

Now, to get the velocity equation, we need to integrate the acceleration over time, we will get:

V(t) = (-32.17 ft/s^2)*t + V0

Where V0 is the initial velocity of the light bulb. Because it is dropped, the initial velocity will be zero, then V0 = 0m/s, then the velocity equation is:

V(t) = (-32.17 ft/s^2)*t

Finally, to get the position equation we need to integrate again, we will get:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + P0

Where P0 is the initial height of the object, and in this case, we know that it is equal to 25 ft.

Then the position equation is:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + 25ft

The object will hit the ground when P(t) = 0 ft, then we need to solve that equation for t:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + 25ft = 0 ft

25 ft = (1/2)*(32.17 ft/s^2)*t^2

2*25ft = (32.17 ft/s^2)*t^2

50ft = (32.17 ft/s^2)*t^2

√( 50ft/(32.17 ft/s^2)) = t = 1.25 s

The light bulb will reach the ground 1.25 seconds after it is dropped.

8 0

3 years ago

Please help no fake answers or links please

Tems11 [23]

D none of them fit the data set.

7 0

3 years ago

Read 2 more answers