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4 years ago

Solve: −4d − 6 = −10

Mathematics

2 answers:

Stels [109]4 years ago

8 0

Answer:

Step-by-step explanation:

$- 4d - 6 = - 10 \\ - 4d = - 10 + 6 \\ - 4d = - 4 \\ d = 1$

i think so…

Andrew [12]4 years ago

8 0

Answer:

_4d=_10+6

_4d=_4

_4/_4d=_4/_4

d=1

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The difference between the solutions to the equation x2 =a is 30 what is a ?

Mademuasel [1]

Given equation is $x^2 = a$

In general solution of $x^2 = b$ is $x = + \sqrt{b}$ and $x = - \sqrt{b}$

So the solution of given equation is $x = + \sqrt{a}$ and $x = - \sqrt{a}$

Now difference between them is 30.
So we can write
$\sqrt{a} - (- \sqrt{a}) = 30$
$\sqrt{a} + \sqrt{a} = 30$
$2 \sqrt{a} = 30$
$\sqrt{a} = 15$

On squaring both side
$( \sqrt{a})^2 = (15)^2$
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4 years ago

Select the correct answer from the drop-down menu.

ELEN [110]

Missing term = –2xy

Solution:

Let us first find the quotient of $-8x^2y^3 \div xy$ .

$-8x^2y^3 \div xy=\frac{-8x^2y^3 }{xy}$

$=\frac{-8\times x\times x\times y\times y\times y}{xy}$

Taking common term xy outside in the numerator.

$=\frac{xy(-8\times x\times y\times y)}{xy}$

Both xy in the numerator and denominator are cancelled.

$=-8xy^2$

Thus, the quotient of $-8x^2y^3 \div xy$ is $-8xy^2$ .

Given the quotient of $-8x^2y^3 \div xy$ is same as the product of 4xy and ____.

$-8xy^2=4xy$ × missing term

Divide both sides by 4xy, we get

⇒ missing term = $\frac{-8xy^2}{4xy}$

Cancel the common terms in both numerator and denominator.

⇒ missing term = –2xy

Hence the missing term of the product is –2xy.

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3 years ago

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