Please help and give me an explanation I don’t understand or know if it’s correct
1 answer:
Hello :) we got similar answers but i believe you made a few distributing mistakes! hopefully my work makes sense, if not i’ll totally try to explain more
p.s i might be too late whoops
p.p.s i’m in a higher grade but i haven’t done this kinda math in a longgg time haha so if you think i did something wrong trust your gut ✌️
p.s i might be too late whoops
p.p.s i’m in a higher grade but i haven’t done this kinda math in a longgg time haha so if you think i did something wrong trust your gut ✌️
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There are 
total possible ways to pick any three integers from the set.
Of the total, there are 18 consisting of consecutive triplets
.
Now, of the total, suppose you fix two integers to be consecutive. There would be 19 possible pairs
, and for each pair 18 possible choices for the third integer (for instance, 
can be taken with 3, 4, ..., 20), to a total of 
. To avoid double-counting (e.g. can't go with 3; 
can't go with 1 or 4), we subtract 1 from the extreme pairs and 
(twice), and 2 from the rest (17 times).
So, the number of triplets that don't consist of pairwise consecutive integers is
I don't know how useful this would be to you, but I've verified the count in Mathematica:
In[8]:= DeleteCases[Subsets[Range[1, 20], {3}], x_ /; x[[2]] == x[[1]] + 1 || x[[3]] == x[[2]] + 1] // Length
Out[8]= 816
Of the total, there are 18 consisting of consecutive triplets
Now, of the total, suppose you fix two integers to be consecutive. There would be 19 possible pairs
So, the number of triplets that don't consist of pairwise consecutive integers is
I don't know how useful this would be to you, but I've verified the count in Mathematica:
In[8]:= DeleteCases[Subsets[Range[1, 20], {3}], x_ /; x[[2]] == x[[1]] + 1 || x[[3]] == x[[2]] + 1] // Length
Out[8]= 816
The answers are
1.
2.
3.
What are fractions?
Any number of equal parts is represented by a fraction, which also represents a portion of a whole. In ordinary English, a fraction refers to the number of parts of a specific size.
We are given,
1.
As the denominator of both fractions are same we add the numerator
We get,
2.
As the denominator of both the fractions are same we subtract the value in the numerator we get,
3.
We first simplify the first term of the equation,
Now as the denominator is not same we use cross multiplication to perform the operation
On further simplifying we get,
Hence the answers are
1. 1
2.
3.
To refer more about the fraction please refer
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