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sweet [91]
4 years ago
11

The table shows the ingredients used in a medicine. If all the decimals were rounded to the nearest whole percent, would this ta

ble be helpful in comparing the amount of each ingredient? Explain.
Mathematics
2 answers:
stira [4]4 years ago
8 0

Answer:whats the answer

Step-by-step explanation:

alekssr [168]4 years ago
6 0

I provided the following answer in a similar question that I answered earlier: 

Not really. Lets say you have 19.8% of x ingredient, 20.7% of y ingredient, 30.6% of m ingredient ad 28.9% of k ingredient. For this medicine, the values would be rounded of to 20%, 21%, 31% and 29%....which adds up to 101%. So by rounding of to he nearest whole percent, you get a total percentage of more than 100%. This would be seen in the other medicines used in 'the table'. The fact that the total percentage for each one would add up to different values each time and not be constant makes the comparison invalid because the conditions being compared would be different. 

You have failed to provide the actual table, so I tried to do my best to come up with example figures to help you answer the question using the figures you have.

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The first rule you need to know is

(a^b)^c=a^{bc}

So, you have

\dfrac{(x^{25})^{-6}}{(x^{-3})^{48}}=\dfrac{x^{25\cdot(-6)}}{x^{-3\cdot 48}}=\dfrac{x^{-150}}{x^{-144}}

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