<span> we know the length of the cable is 9m. That means the magnitude of </span><span><span>r<span><span><span>AB</span></span><span></span></span></span>=9</span><span>m. The unit vector, denoted u, is each of </span><span>r<span><span><span>AB</span></span><span></span></span></span><span> divided by the magnitude.
</span></span><span>We can also figure out the unit vector of F. </span>u=(350i - 250j - 450k)/√(350² +(-250)² +(-450)²) u=0.562i−0.401j−0.723<span>k </span> <span>Force F is directed from point A to B, then both unit vectors must be equal.
Therefore </span>(x/9i−y/9j−z/9k)=0.562i−0.401j−0.723k <span>We can now solve for each term x/9=0.562----- > x=5.058 m -y/9=-0.401--------- > y=3.609 m -z/9=-0.723------- > z=6.507 m
The answer is the coordinates of point a (5.058,3.609,6.507) </span>