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2 years ago

14

Stuck on this question: Solve 6(2y-3)-10=2y

2 answers:

Dmitrij [34]2 years ago

8 0

Answer:

Exact form: y = $\frac{14}{5}$

Decimal form: y = 2.8

Step-by-step explanation:

Distribute:

6(2y - 3) - 10 = 2y

12y - 18 - 10 = 2y

Subtract the numbers:

12y - 18 - 10 = 2y

12y - 28 = 2y

Add 28 to both sides:

12y - 28 = 2y

12y - 28 + 28 = 2y + 28

Simplify:

Add the numbers

12y = 2y + 28

Subtract 2y from both sides:

12y = 2y + 28

12y - 2y = 2y + 28 - 2y

Simplify:

Combine like terms

10y = 28

Divide both sides by the same factor:

10y = 28

10y/10 = 28/10

Simplify:

Cancel terms that are in both the numerator and denominator

Divide the numbers

y = 14/5

shtirl [24]2 years ago

6 0

Y= 2 4/5 or 2.8 in decimal form

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Step-by-step explanation:

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3 years ago

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2 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

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Answer:

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Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

so

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

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substitute

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Step 2

Find the perimeter of the figure

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Applying Pythagoras theorem

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Remember that

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$r=6/2=3\ cm$

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$C=3 \pi\ cm$

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Simplify

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