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1 year ago

Stuck on this question: Solve 6(2y-3)-10=2y

Mathematics

2 answers:

Dmitrij [34]1 year ago

8 0

Answer:

Exact form: y = $\frac{14}{5}$

Decimal form: y = 2.8

Step-by-step explanation:

Distribute:

6(2y - 3) - 10 = 2y

12y - 18 - 10 = 2y

Subtract the numbers:

12y - 18 - 10 = 2y

12y - 28 = 2y

Add 28 to both sides:

12y - 28 = 2y

12y - 28 + 28 = 2y + 28

Simplify:

Add the numbers

12y = 2y + 28

Subtract 2y from both sides:

12y = 2y + 28

12y - 2y = 2y + 28 - 2y

Simplify:

Combine like terms

10y = 28

Divide both sides by the same factor:

10y = 28

10y/10 = 28/10

Simplify:

Cancel terms that are in both the numerator and denominator

Divide the numbers

y = 14/5

shtirl [24]1 year ago

6 0

Y= 2 4/5 or 2.8 in decimal form

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Answer:

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Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$

$\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}$

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3 years ago

The vertex of the parabola below is at the point (2, 4), and the point (3, 6) is on the parabola. what is the equation of the pa

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Given:

Vertex ===> (h, k) (2, 4)

The parabola passes through the point: (x, y) ==> (3, 6)

Let's find the equation of a parabola.

To find the equation, use the general equation of a parabola with vertex (h, k):

$y=a(x-h)^2+k_{}$

Where:

(h, k) ==> (2, 4)

(x, y) ==> (3, 6)

Substitute values into the general equation:

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Subtract 4 from both sides:

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Substitute 2 for a, and input the values of the vertex (h, k) in the general vertex equation:

$y=2(x-2)^2+4$

Therefore, the equation of the parabola is:

$y=2(x-2)^2+4$

ANSWER:

$y=2(x-2)^2+4$

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10 months ago

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Step-by-step explanation:

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[tex]A=\pi \times 7.25 \times 7.25[/text]

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[tex]A=\pi \times 7.25 \times 7.25[/text]

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Area is 165.046 Sq Ft

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For 1 sq ft of fields the fertiliser needed =

[tex]\frac{2}{25}[/text] tea spoon

For 165.046 sq ft of fields the fertiliser needed =

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Answer:

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