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kenny6666 [7]
4 years ago
11

Help ASAP BRAIN IF RIGHT The width of a rectangle is 12 units. Can the perimeter P of the rectangle be 60 units when its length

x is 18 units?
No, because P ≠ 2x + 2(12)
No, because P = 2x + 2(12)
Yes, because P ≠ 2x + 2(12)
Yes, because P = 2x + 2(12)
Mathematics
1 answer:
bonufazy [111]4 years ago
6 0

Answer:

Yes, because P = 2x +2(12)

Step-by-step explanation:

As the formula for perimeter is 2(L+B).

Let L=x=18

B=12

Then, perimeter, P=2(18+12) = 2(30) = 60

Hence, we get the perimeter as 60 units.

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Solve each system by elimination by multiplying both equations. eliminate y first. show all work.
Alex17521 [72]
First \mathrm{Multiply\:}10x-3y=18\mathrm{\:by\:}3:\quad 30x-9y=54
Then \mathrm{Multiply\:}6x-10y=-22\mathrm{\:by\:}5:\quad 30x-50y=-110
To get \begin{bmatrix}30x-9y=54\\ 30x-50y=-110\end{bmatrix}
So...
30x-50y=-110 \ \textgreater \  \begin{bmatrix}30x-9y=54\\ -41y=-164\end{bmatrix}
-41y=-164 \ \textgreater \  \mathrm{Divide\:both\:sides\:by\:}-41 \ \textgreater \  \frac{-41y}{-41}=\frac{-164}{-41}
To get y = 4.
\mathrm{For\:}30x-9y=54\mathrm{\:plug\:in\:} \:y=4 \ \textgreater \  30x-9\cdot \:4=54
\mathrm{Multiply\:the\:numbers:}\:9\cdot \:4=36 \ \textgreater \  30x-36=54 \ \textgreater \
Next \mathrm{Add\:}36\mathrm{\:to\:both\:sides} \ \textgreater \  30x-36+36=54+36 \ \textgreater \  \mathrm{Simplify} \ \textgreater \  30x=90
Finally \mathrm{Divide\:both\:sides\:by\:}30 \ \textgreater \  \frac{30x}{30}=\frac{90}{30} \ \textgreater \  x = 3
Therefore our solutions are y = 4, x = 3
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Answer:

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Step-by-step explanation:

Use trigonometry.

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