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laiz [17]
1 year ago
10

A building is 5 feet tall. the base of the ladder is 8 feet from the building. how tall must a ladder be to reach the top of the

building? explain your reasoning.show your work. round to the nearest tenth if necessary.
Mathematics
1 answer:
iris [78.8K]1 year ago
5 0

The ladder must be 9.4 ft to reach the top of the building

Here, we want to get the length of the ladder that will reach the top of the building

Firstly, we need a diagrammatic representation

We have this as;

As we can see, we have a right triangle with the hypotenuse being the length of the ladder

We simply will make use of Pythagoras' theorem which states that the square of the hypotenuse is equal to the sum of the squares of the two other sides

Thus, we have;

\begin{gathered} x^2=5^2+8^2 \\ x^2=\text{ 25 + 64} \\ x^2\text{ = 89} \\ x=\text{ }\sqrt[]{89} \\ x\text{ = 9.4 ft} \end{gathered}

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Crank
Hi!

If she worked 18 hours last week and 20 hours this week, then she worked 38 hours in total, because 18 + 20 = 38.

If she earns $6 per hour, and she worked for 38 hours, then she got 38 sets of 6, which you can find the answer to by multiplying 38 and 6.

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(\stackrel{x_1}{1}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{4}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

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5y-x=10\\\\ 5y=10+x \ |:5 \ Both \ sides \\\\ y=\frac{10}{5}+\frac{x}{5}\\\\ y=2+\frac{x}{5}

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