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WARRIOR [948]
3 years ago
7

4x-5=6x+13 What is the first step in solving equations

Mathematics
2 answers:
expeople1 [14]3 years ago
8 0

Answer:

4x-6x=13+5

-2x=18

x=18/-2=-9

please follow me!!

laiz [17]3 years ago
4 0

Answer:

x=-7.5

Step-by-step explanation:

Create a numeral side and variable side and put them in the right sid you will get -13-5=6x-4x

-15=2x   divide 2x by 2 then -5  by 2

x=-7.5

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Help me❤️!!!!!!!!!!!
sweet-ann [11.9K]

Answer:

B

Step-by-step explanation: Because for inverse functions, domain and range of functions exchange. In simple words, domain of function h(x) = range of inverse function & range of function h(x) = domain of inverse function.

5 0
2 years ago
A rocket is fired with an initial vertical velocity of 40 m/s from a launch pad 45 m high, and its height is given by the formul
N76 [4]

Answer:

1) 125 meters

2) For 9 seconds.

Step-by-step explanation:

The rocket's height is given by the formula -5t^2+40t+45.

Notice that this is a quadratic.

Part 1)

Since this is a quadratic, the highest height the rocket goes will be the vertex of our quadratic. Remember that the vertex of a quadratic in standard form is:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

So, let's identify our coefficients. The standard quadratic form is:

ax^2+bx+c

Therefore, in this case, our a is -5, b is 40, and c is 45.

So, let's find the x-coordinate of our vertex. Substitute 40 for b and -5 for a. This yields:

x=\frac{-(40)}{2(-5)}

Multiply and reduce. So:

x=-40/-10=4

Now, substitute 4 for t to find the height. So:

-5(4)^2+40(4)+45

Evaluate:

=-5(16)+40(4)+45

Multiply and add:

=-80+160+45=125\text{ meters}

Therefore, the highest the rocket goes up is 125 meters.

Part 2)

To find out for how much time the rocket is in the air, we can think about after how many seconds after launch will the rocket land.

If the rocket lands, the height h will be 0. So, we can set our expression equal to 0 and solve for t:

-5t^2+40t+45=0

First, let's divide everything by -5. This yields:

t^2-8t-9=0

We can factor:

(t+1)(t-9)=0

Zero Product Property:

t+1=0\text{ or } t-9=0

Solve for t:

t=-1\text{ or } t=9

In this case, since t is our time in seconds, -1 seconds does not make sense. So, we can remove -1 from our solution set.

Therefore, 9 seconds after launch, the rocket will touch the ground.

Therefore, the rocket was in the air for 9 seconds.

And we're done!

6 0
4 years ago
Find the length of BC. <br> A.) 14<br> B.) 9<br> C.) 2<br> D.) 3
Vera_Pavlovna [14]

Answer:

A) 14

Step-by-step explanation:

BC is congruent to DC in saying this you can plug the equations to each other and solve for y and then put its back into the equation for BC to get the length.

3y+5=5y-1

subtract 3y from both sides --> 5=2y-1

add 1 to both sides --> 6=2y

now get y alone, divide by 2 by both side --> y=3

plug y in back to 5y-1 --> 5x3-1

15-1

BC = 14

7 0
3 years ago
THIS IS URGENTE I AM BEING TIMED PLZ HELP, if you answer both correct i will mark you brainlyist
Lapatulllka [165]
Area would be 4.52 A= pi x radius squared
Circumference would be 7.54 C= 2 pi radius. Hope that makes sense.
4 0
3 years ago
A snake bar sold 12 1/2 gallons of milk at 35 cents a pint. How much did the snack bar receive for the milk
stepladder [879]

9514 1404 393

Answer:

  $35.00

Step-by-step explanation:

The number of pints sold is ...

  (12.5 gal)×(8 pt/gal) = 100 pt

Then the total amount received for the milk is ...

  (100 pt)($0.35/pt) = $35.00

8 0
2 years ago
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