While exercising Ricardo walked 1/8 of a mile in 1/9 of an hour. At this rate, how far will he have travelled after an hour?

1 answer:

6 0

$\bf \begin{array}{ccll} miles&hours\\ \cline{1-2}\\ \frac{1}{8}&\frac{1}{9}\\\\ x&1 \end{array}\implies \cfrac{~~\frac{1}{8}~~}{x}=\cfrac{~~\frac{1}{9}~~}{1}\implies \cfrac{~~\frac{1}{8}~~}{\frac{x}{1}}=\cfrac{1}{9}\implies \cfrac{1}{8x}=\cfrac{1}{9} \\\\\\ 9=8x\implies \cfrac{9}{8}=x\implies 1\frac{1}{8}=x$

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Answer:

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2 years ago

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The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E

Gnoma [55]

Answer:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

Step-by-step explanation:

Given

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$AC = 10$

$AB = 5$

$\angle C = 30^\circ$

$ED = 7.5$

$DF = 25$

$\angle F =30$

$\angle E =90$

Required

Which of the options is/are true:

$\triangle CBA {\displaystyle \sim } \triangle FED$ $\triangle CBA {\displaystyle \sim } \triangle FDE$ $\triangle BAC {\displaystyle \sim } \triangle EFD$

$\triangle BAC {\displaystyle \sim } \triangle EDF$ $\triangle ABC {\displaystyle \sim } \triangle DE\ F$ $\triangle ABC {\displaystyle \sim } \triangle DFE$