The answer is c. Anaphase I separates homologous chromosomes and anaphase II separates sister chromatids into daughter cells.
Meiosis is a cell division which results in the reduction of chromosome number by half (from diploid to haploid) in daughter cells. It consists of meiosis I and meiosis II.
In anaphase I, the sister chromatids separate from each other to the opposite sides of the cells. In meiosis I there are 46 chromosomes in duplicates which are present as pairs of sister chromatids. When comes to separation, homologous chromosomes separates only, but not sister chromatids. Homologous chromosomes are present only in meiosis I.
In anaphase II, since the cell is haploid, there are 23 chromosomes in duplicates, which are present as sister chromatids. So, in this phase, sister chromatids are those who separates.
Answer:
Maltose is a disaccharide sugar made up of two units of glucose.
In cyclic structure, the glucose exists in two anomeric forms; alpha and beta.
These glucose units can either joined by α (1→4) glycosidic bond or by β (1→4) glycosidic bond.
Thus, the maltose exists in two anomeric form alpha and beta.
Answer:
The correct answer is: D. Ebola.
Explanation:
- Ebola Virus is a single-stranded RNA (ribonucleic acid) virus.
- The natural host of the virus is Fruit bat but it can also infect humans.
- The transmission of the virus into humans is mediated from infected bats through body fluids.
- The major disease caused by the virus is is Hemorrhagic fever. In this disease, the platelet (responsible for clotting of blood) count in the blood drops far below normal. As a result, bleeding can get initiated both in the body interior or exterior. This disease can cause multiple organ failure and death.
- Recently, in the year 2018, the Central African country, Democratic Republic of Congo experienced a severely fatal endemic due to the Ebola virus that killed many people within a short period of time.
