Answer:B
Explanation:
This reaction demonstrated Bohr effect. it takes place in the cytoplasm of RBC , because this is the location of the enzyme carbonic anhydrase which catalyzed it .
The hydrogen ion and bicarbonate are transferred out of the RBC into plasma. Chloride ion diffused into the RBC to neutralize drop in pH(chloride shift).
The hydrogen ion is mobbed by haemoglobin in its buffer effect, while the carbonate is transferred to the lungs where it is broken down, to release C02 .85% of blood C02 is transported in this form .
The CO2 released out of the lungs , created a concentration gradient for influx of Oxygen into the lungs. This is the significance of this reaction.
In addition, Option D which involved direct reaction of C02 with Haemoglobin to form carbaminoheamoglobin is another reaction which takes place in the RBC. it is a reversible reaction where the C02 is transported to the lungs.10% C02 is tranported in this form,
The answer would probably be camouflage depending on the answers.
I believe the answer is acetyl CoA
Answer:
A. It results in the number of chromosomes being reduced by half.
Explanation:
In the process of meiosis, one cell is divided 2 times to form 4 daughter cells. These 4 daughter cells have half the number of chromosomes that of the parent cell.
