Given:
are in geometric sequences.
To find:
The value of x.
Solution:
If a, b, c are in geometric sequences, then
...(i)
It is given that are in geometric sequences. By using (i), we get
On further simplification, we get
Therefore, the value of x is 0.
Answer:
The number of messages that will cost same both plans is <u>1000</u>.
Step-by-step explanation:
Given,
For 1st offer:
Total number of messages = 500
Charge of each message after 500 messages = $0.10
For 2nd offer:
Total number of messages = 400
Charge of each message after 400 messages = $0.20
We need to find out the number of messages can be sent for equal cost of both plans.
Solution,
Let the number of messages be 'm'.
So For 1st offer:
Total cost 'c' is equal to fixed cost for 500 messages plus charge of each message multiplied with number of messages.
framing in equation form, we get;
Again for 2nd offer:
Total cost 'c' is equal to fixed cost for 400 messages plus charge of each message multiplied with number of messages.
framing in equation form, we get;
Now the question said that the charge would be the same.
So we can say that;
On combining the like terms, we get;
Now using multiplication property, we will multiply both side by '10' and get;
Hence The number of messages that will cost same both plans is <u>1000</u>.
Answer:
-6, -5, -1
Step-by-step explanation:
Based on the question, (x+6) is a factor of f(x).
With this, you can do the long division method of dividing f(x) with (x+6) {Refer to the image}.
You'll get x²+6x+5 as a result.
Factorise it and you'll get
x²+6x+5 = (x+1)(x+5)
Then let (x+1)(x+5) = 0, x = -1, -5
Zero's of f(x) are -6, -5 -1
