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satela [25.4K]
2 years ago
10

Find xif 4; 4+2×;4+4× are in Geometric sequences​

Mathematics
1 answer:
Ray Of Light [21]2 years ago
7 0

Given:

4,4+2x,4+4x are in geometric sequences​.

To find:

The value of x.

Solution:

If a, b, c are in geometric sequences​, then

\dfrac{b}{a}=\dfrac{c}{b}

b^2=ac           ...(i)

It is given that 4,4+2x,4+4x are in geometric sequences​. By using (i), we get

(4+2x)^2=(4)(4+4x)

4^2+2(4)(2x)+(2x)^2=(4)(4)+4(4x)

16+16x+4x^2=16+16x

4x^2=16+16x-16-16x

On further simplification, we get

4x^2=0

x^2=0

x=0

Therefore, the value of x is 0.

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Answer:

1. $25

2. 12

3. -12

4. -12

5.  -25

Step-by-step explanation:

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5E. Express the given fraction below in the simplest form.
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Answer:

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Step-by-step explanation:

3 1/3 can be written as 10/3

then we have 3/10/3 we then have 3x3/10 which equals 9/10.

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2 years ago
If a number is odd, then it has a remainder of 1 when divided by 2.
kherson [118]

Answer:

The hypothesis of the conditional is "<em>A number is odd</em>".

Step-by-step explanation:

The statement can be represented by the following proposition:

P \implies Q (Eq. 1)

Where:

P is the hypothesis of the proposition.

Q is the conclusion of the proposition.

\implies - Binary connector, which means "If...., then...."

In this case, we present what each propostion represents:

P = A number is odd.

Q = It has a remainder of 1 when divided by 2.

In consequence, the hypothesis of the conditional is "<em>A number is odd</em>".

6 0
3 years ago
The equation of a circle is given below. x^{2}+(y-2.25)^{2} = \dfrac{196}{169}x 2 +(y−2.25) 2 = 169 196 ​ x, squared, plus, left
Lostsunrise [7]
  • Center =(h,k) = (0,2.25)
  • Radius = r = \frac{14}{13}

<u>Step-by-step explanation:</u>

Here we have following equation : x^{2}+(y-2.25)^{2} = \dfrac{196}{169}

We need to find the center & radius of this circle . Let's find out:

We know that , Equation of a circle is given by :

⇒ (x-h)^2+(y-k)^2=r^2   ........(1)

Here , (h,k) are the co-ordinates of center & r is the radius of circle.Collectively called as a circle with radius r and center at (h,k) . Let's frame given equation in question :

⇒  x^{2}+(y-2.25)^{2} = \frac{196}{169}

⇒  (x-0)^{2}+(y-2.25)^{2} = (\frac{14}{13})^2

On comparing this equation with equation (1) we get :

  • Center =(h,k) = (0,2.25)
  • Radius = r = \frac{14}{13}
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Answer:Yes i do

Step-by-step explanation:

Your welcome :)

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