ANSWER

EXPLANATION
The given series is

The first term of the series is,

The common ratio of this series is,

This simplifies to,

The sum to infinity of this sequence is given by the formula,

We substitute the above values into the formula to obtain,

This simplifies to,

We simplify the denominator to get,

This will finally give us,


The correct answer is A.
Is it P (q+r ) or P( q, r)?
Answer:
1,2,3,4,5,6,7,8,9,10
2,4,6,8,10,12,14,16,18,20
3,6,9,12,15,18,21,24,27,30
Step-by-step explanation: