Answer:
High heat and pressure cause the rocks to become metamorphic. presses and presses down onto the rock, making it stay and compress down
Reproductive strategy is loosely used to refer to the way an animal mates and/or raises offspring
The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB
Answer:
Structure X is only found in plant cells, and structure Y is found in plant and animal cells.
Explanation:
The structure found on the outside of the onion cell is the cell wall, which is specific to plants. The structure found on the outside of the skin cell is the cell membrane, which is found on all cells.
Structure X is not living, and structure Y is living. - this is false, both animal and plant cells are living.
Structure X can be found in some human cells, and structure Y can be found in some plant cells. - this is false, the opposite is true.
Structure X is only found in plant cells, and structure Y is found in plant and animal cells. - this is true structure X is the plant cell wall, and structure Y is the cell membrane
Structure X is semipermeable, and structure Y is selectively permeable. Semi-permeable and selectively permeable are essentially the same thing - it means the barrier allows some substances to pass through but not others.
Va graph will say that the amount of viruses taken it will 1000 viruses
