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k0ka [10]
3 years ago
11

Given g(x) how do I find the 4 right endpoint rectangles

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
8 0

use a calculator girl u smarter than this

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The chemical element einsteinium-
AURORKA [14]

Answer:

Every week, the mass of the sample is multiplied by a factor of 0.81

Step-by-step explanation:

Let's rewrite the base and find the expression whose exponent is just ttt.

(0.97)7t+5=(0.97)7t⋅(0.97)5=(0.977)t⋅(0.97)5

Therefore, we can rewrite the modeling function as follows.

M(t)=(0.97)5⋅(0.977)t

According to this model, the mass of the sample is multiplied by 0.977 every week. Rounding this to two decimal places, we get 0.977≈0.81.

7 0
3 years ago
Jade is thinking of a number. 3/4 of 200 is the same as 1/8 of her number. What number is she thinking of?
lorasvet [3.4K]

Answer:

1200

Step-by-step explanation:

3/4 of 200 = 150

150 is 1/8 of 1200

5 0
3 years ago
Read 2 more answers
A train is traveling at 60 mph. If the rate of speed increases 4 mph each hour,
Alenkasestr [34]

Answer:

B) 5 hours

Step-by-step explanation:

First, find the amount of mph between 60 and 80:

80 - 60

= 20 mph

Since the speed increases 4 mph per hour, we can find how long it will take to get to 80 mph by dividing 20 by 4:

20/4

= 5

So, the correct answer is B, 5 hours

6 0
2 years ago
3. How many turning points does the graph P(x) = (x-7)(x + 4)(x-2)
mixer [17]

Answer:

The y intercept in P(x) =4

1.C

3.B

3 0
3 years ago
There are 5 pens in a container on your desk. Among them, 3 will write well but 2 have defective ink cartridges. You will select
Norma-Jean [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Total Number of pens = 5

Number of defective pens = 2

Number of non-defective pens = 3

A.) number of defective pens selected :

X : {0, 1, 2}

It is possible that no defective pen will be selected ; 1 defective will be chosen or both pens are defective.

2.)

Defective as Success (since selecting a defective pen is the point of interest.

3.)

Since selection is done without replacement

Probability of success per selection is different for each selection ;

Number of defective = 2

Number of observations = 5

P(success on first selection) = 2/5

P(success on second selection) = 1/4

Hence, X is not well approximated by a binomial random variable.

4.) if selection is done with replacement ; then then the probability of success per selection will be the Same for each selection made. Hence, X will be well approximated by a binomial Random variable.

5.) If sampling is done without replacement, then the the hypergeometric function will be a more effective approximation.

7 0
3 years ago
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