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MAVERICK [17]
3 years ago
10

Jade is thinking of a number. 3/4 of 200 is the same as 1/8 of her number. What number is she thinking of?

Mathematics
2 answers:
miv72 [106K]3 years ago
7 0

Answer:

1200

Step-by-step explanation:

3/4 of 200 is 150

is 150 is 1/8 of her number then multiply 150 by 8 and you get her number.

lorasvet [3.4K]3 years ago
5 0

Answer:

1200

Step-by-step explanation:

3/4 of 200 = 150

150 is 1/8 of 1200

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He needs to purchase some work clothes and notices that J.C. Penney is having a 25% off of your total purchase sale. He decides
SVETLANKA909090 [29]
First, lets determine the regular price of his purchase :

16.99 (3) + 34.99 (3) + 52.99 (2) + 5.99 (5) = 50.97 + 104.97 + 105.98 + 29.95 = 291.87

Therefore, the regular price of his purchase is $291.87 before sales tax.

If he receives 25% off of his total purchase, then the price is now :

291.87 * .75 = $218.90

We multiply by 75% because we are only paying 75% of the total purchase price since we received a 25% discount.

The total savings is 

291.87 - 218.90 = $72.97

If sales tax is 10%, the total purchase price after sales tax is :

218.90 * 1.10 = $240.79

The sales tax is $21.89 since

240.79 -218.90 = 21.89

If he pays with 3 $100 bills, we should receive :

300 - 240.79 = $59.21 

in change.
5 0
3 years ago
Choose the equation that is equivalent to this statement. 9090 is 70% of x.
Zolol [24]
9090 is 70% of 12,985.7143
5 0
3 years ago
How many miles are in 8,216 feet​
GarryVolchara [31]

Answer:

1.556061

Step-by-step explanation:

you need to divide the length value by 5280

3 0
3 years ago
Read 2 more answers
I need help with 1 and 3 please
schepotkina [342]
For #1
city A's mean would be 10.5, then you would divide it by the number of numbers there is which is 5,So 10.5/5 is 2.1

city B's mean would be 11.6  then you would divide it by the number of numbers there is which is 5, So 11.6/5 is 2.32.

thats all I have don't know how to do #3 sorry 
4 0
3 years ago
Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}

From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
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