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lianna [129]
3 years ago
12

A rational number can be written as the ratio of one blank to another and can be represented by a repeating or blank decimal

Mathematics
2 answers:
DaniilM [7]3 years ago
6 0
<span>A rational number can be written in the form:

</span>\frac{p}{q}; \  called \ the \ ratio \\ \\ where \ p \ and \ q \ are \ whole \ numbers<span>

The number $q$ isn't equal to zero because the division by zero is not defined. So we can represent rational numbers by a repeating or terminating decimal, for instance in the following four exercises we have:

</span>\frac{2}{3}=0.6666...=0.\stackrel{\frown}{6} \\ \\ \frac{5}{8}=0.625000...=0.625\stackrel{\frown}{0} \\ \\ \frac{3}{1}=3.000...=3.\stackrel{\frown}{0} \\ \\ \frac{3446}{2475}=1.392323...=1.39\stackrel{\frown}{23}<span>
</span>
Nesterboy [21]3 years ago
6 0

we know that

A rational number is the quotient of two integers with a denominator that is not zero , and can be represented by a repeating or terminating decimal.

Repeating Decimal is a decimal number that has digits that go on forever

Terminating decimal is a decimal number that has digits that do not go on forever.

examples

\frac{1}{3} = 0.333... (the 3 repeats forever)----> Is a Repeating Decimal

0.25 (it has two decimal digits)----> Is a Terminating Decimal

therefore

the answer is

A rational number can be written as the ratio of one integer to another and can be represented by a repeating or terminating decimal

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Answer:

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Step-by-step explanation:

The equation of a line has the following format:

y = mx + b

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I am going to choose (0,3) and (1,3)

(0,3)

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y = mx + b

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(1,3)

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The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0
3 years ago
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