Answer:
505.4 in²
Step-by-step explanation:
½d2= 19×tan 35° = 19×0.7 = 13.3 in
d2 = 2×13.3 = 26.6 in
d1 = 2×19=38 in
the area of Rhombus =
½×38×26.6 = 505.4 in²
1)5/24
2)1 and 1/3 im not sure
3)1 and 1/3
4)1/7
Answer:
Yes, A KLP can be reflected across the line containing KP and then translated so that Pis mapped to M.
Step-by-step explanation:
The figure shows two congruent by HA theorem (they have congruent hypotenuses and a pair of congruent angles adjacent to the hypotenuses) triangles KLP and QNM.
A rigid transformation is a transformation which preserves lengths. Reflection, rotation and translation are rigit transformations.
If you reflect triangle KLP across the leg KP and translate it up so that point P coincides with point M , then the image of triangle KLP after these transformations will be triangle QNM.
Let the two numbers be x and y.
Let m = the fraction (or percentage) for increasing the numbers.
Increase x by 5, multiply (x+5) by (1+m), and set it qual to 36.
(x + 5)*(1 + m) = 36
Increase y by 5, multiply (y+5) by (1+m), and set it equal to 36.
(y+5)*(1+m) = 36
Therefore
(x+5)*(1+m) = (y+5)*(1+m)
x + 5 = y + 5
x = y
x - y = 0
Answer: 0.
The difference between the two numbers is zero.
log(x) + log(3) = log(18)
log(x) + 0.477121 = 1.255273
Add -0.477121 to both sides.
log(x) + 0.477121 + −0.477121 = 1.255273 + −0.477121
log(x)+0 = 0.778152
Divide both sides by 1.
log(x)+0/1 = 0.778152/1
log(x)=0.778152
Solve Logarithm
log(x) = 0.778152
10log(x) = 100.778152
x = 100.778152
x = 6.00001
