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4 years ago

What happened to www.brainy.com?

Mathematics

2 answers:

Anna35 [415]4 years ago

6 0

As far as I'm concerned, it still exists

Keith_Richards [23]4 years ago

6 0

What do you mean becauae nothing happened

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Calculate the unpaid balance, finance charge, and new balance using the unpaid balance method. Note: interest rate is given as a

Karolina [17]

Answer:

The new balance will be $385.04.

Step-by-step explanation:

Previous balance = $179.32

Payments/credits = $85.00

Unpaid balance = $179.32+85$ = $264.32

Monthly rate = 1.25%

Finance charge = $0.0125\times264.32$ = $3.30

New purchases = $117.42

New balance = $264.32+3.30+117.42$ = $385.04

5 0

3 years ago

Read 2 more answers

What integer is the closest to 731

guajiro [1.7K]

Answer:

731 is an integer. An Integer is a whole number!

Step-by-step explanation:

6 0

3 years ago

Find the annual interest rate.

slega [8]

The annual interest rate is 3.5%.

Solution:

Given Interest (I) = $26.25

Principal (P) = $500

Time (t) = 18 months

Rate of interest (r) = ?

Time must be in years to find the rate per annum.

1 year = 12 months

Divide the time by 12.

Time (t) = $\frac{18}{12}=\frac{3}{2}$ years

Now, find the rate of interest using simple interest formula.

<u>Simple interest formula:</u>

$$I=\frac{Prt}{100}$

$$26.25=\frac{500\times r\times \frac{3}{2} }{100}$

$$26.25\times 100 =500\times r\times \frac{3}{2}$

$$2625 =250\times r\times 3$

$$2625 =750\times r$

$$\Rightarrow r=\frac{2625}{750}$

⇒ r = 3.5%

Hence the annual interest rate is 3.5%.

8 0

3 years ago

Jamal is running 42 kilometers. The amount of time t it takes Jamal to run varies inversely with the rate, r, at which he runs,

leva [86]

Answer:

t α 1 /r ; t = k/r

Step-by-step explanation:

Given that :

Time taken, t varies inverse as rate, r

MATHEMATICALLY,

t α 1 /r

Hence,

t = k/r ;

Where, k is the proportionality constant

Hence, the situation could be expressed as :

t = k/r OR

t α 1 /r

6 0

3 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago