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Alona [7]
4 years ago
8

How do you do this Please help

Mathematics
1 answer:
sergejj [24]4 years ago
3 0

Answer:

The answer is 68°.

Step-by-step explanation:

Following the arc length equation:

s = r * θ where s is arc length, r is radius of the circle, and θ is the angle in radians.

12 is the Radius of the Circle and therefore solve for θ:

θ = \frac{s}{r} = \frac{\frac{68\pi }{15} }{12} = \frac{17\pi }{45} rad. or radians

Now, convert the radians to degrees:

\frac{17\pi }{45} = 68°

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Well if the equation is -16t^2 + vt + h0,

and we know v = 30, because that's the velocity,

and we also know h0 = 6 because that's the height,

then the equation will read: -16t^2 + 30t + 6
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Which graph shows the equation y = x - 2?
kondaur [170]

Answer:

Choice A

Step-by-step explanation:

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Solve the following equation by factoring: x^2 - 2x - 48 = 0
Vlada [557]

Answer:

B. x=-6 or x=8

Step-by-step explanation:

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4 years ago
Which of the following steps is needed to inscribe a circle in a triangle?
xxTIMURxx [149]

Construct two angle bisectors of the triangle

Answer:

Option (D) is correct

<u>Step-by-step explanation:</u>

We have to contruct two angle bisectors of the triangle.

various steps to inscribe the circle in a triangle are

  1. First draw a triangle
  2. Draw angle bisector of one angle
  3. Draw angle bisector of another angle
  4. Extent these angle bisectors, where they meet that point will be called the incenter
  5. From incenter draw prependicular to any side of the triangle
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3 years ago
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The intensity of an earthquake with a magnitude of 2 is how many times greater than the intensity of an a standard earthquake ?
Ksju [112]

Answer:  

The intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of a standard earthquake.

Explanation:  

The magnitude of earthquakes is given by

Magnitude=log\frac{I}{S}

2=log\frac{I}{S}\\

Where I is the intensity of earthquake and S is the intensity of standard earthquake.

The magnitude of standard earthquakes is given by

Magnitude=log\frac{S}{S}= log(1) = 0

So comparing the magnitude of the given earthquake and standard earthquake,

log\frac{I}{S} = log\frac{S}{S}

log\frac{I}{S} - log\frac{S}{S}

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2 - 0

2

which means that

10^2 = 100 times greater

Therefore, the intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of a standard earthquake.

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